Dice throw, avg.,standard deviation

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The discussion focuses on calculating the average and standard deviation of a dice throw. The average result, denoted as , is correctly calculated as the sum of the outcomes divided by six. The second moment, , is also computed accurately by averaging the squares of the outcomes. The standard deviation formula σ_x is applied correctly, leading to an approximate value of 0.7825. Overall, the mathematical approach and formulas used in the solution are validated as correct.
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Homework Statement


upload_2017-9-11_16-42-6.png


Homework Equations

The Attempt at a Solution


Let's denote the result of the throw by the variable x.
## <x> = Σ_i P_i x_i , i = 1,2,3,...,6.
\\= \frac{1+2+3+4+5+6}{6}
\\<x^2> = \frac{1^2+2^2+3^2+4^2+5^2+6^2}{6}
\\σ_x = \sqrt{<x^2> - <x>^2} ##
Is this correct?
 
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Your formulas appear to be correct.
you should get a standard deviation of the form: ##\sigma_x \approx ## *.**7825.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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