Dielectric interface plate capacitor at angle alpha

In summary, the conversation discusses determining the E-field inside and outside a dielectric interface at a tilted angle. The equations E_1*sin a_1= E_2* sin a_2 and epsilon_1*E_1*cos a_1 = epsilon_2*E_2*cos a_2 are used to find the parallel and perpendicular components of the E-field inside the dielectric. The electric displacement field D is also mentioned, which represents how an electric field influences the organization of electric charges in a medium. The conversation also raises questions about resolving an oblique E-vector into normal and tangent components and checking the work by line-integrating the new E-vector along its path.
  • #1
lena_2509
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Homework Statement
Consider a plate capacitor with a dielectric interface (\epsilon = \epsilon_0*\epsilon_r, thickness=d) tilted at the angle \alpha . Outside the interface \epsilon = \epsilon_0. Without dielectric interface is the field \vec{E}=E_0*\vec{e_z}. Determine the E-field inside and outside the dielectric interface at the angle \alpha.
Relevant Equations
E_1*sin a_1= E_2* sin a_2
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Consider a plate capacitor with a dielectric interface (\epsilon = \epsilon_0*\epsilon_r, thickness=d) tilted at the angle \alpha . Outside the interface \epsilon = \epsilon_0. Without dielectric interface is the field \vec{E}=E_0*\vec{e_z}.
Determine the E-field inside and outside the dielectric interface at the angle \alpha (a).
My first attempt was to determine the E-field for the parallel and the perpendicular component at the angle \alpha=0 inside and outside the medium.
Inside the medium:
for the parallel component→ E_1*sin a_1= E_2* sin a_2 with a_1 = 0 → E_2=a_2=0
So inside the dielectric interface the parallel component is zero
for the perpendicular component: epsilon_1*E_1*cos a_1 = epsilon_2*E_2*cos a_2 with a_1= 0 → E_2=epsilon_1/epsilon_2* E_1
Outside the medium the electric displacement field D represents how an electric field E influences the organization of electric charges in a given medium. In electric field is D = epsilon_0*E +P.
But how do I determine the field for any other angle alpha ? Could I use the equations from the first attempt with a_1≠0 ?
 
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  • #2
lena_2509 said:
Homework Statement: Consider a plate capacitor with a dielectric interface (\epsilon = \epsilon_0*\epsilon_r, thickness=d) tilted at the angle \alpha . Outside the interface \epsilon = \epsilon_0. Without dielectric interface is the field \vec{E}=E_0*\vec{e_z}. Determine the E-field inside and outside the dielectric interface at the angle \alpha.
Homework Equations: E_1*sin a_1= E_2* sin a_2
View attachment 250691
What changes occur to an E vector normal to an interface between media of differing permittivities as it passes from one medium to another?

What changes occur to an E vector tangent to an interface between media of differing permittivities as it passes from one medium to another?

Can you resolve an oblique E vector into normal and tangent components, determine those changes, and from them determine the new E vector magnitude and direction inside the dielectric?

And can you check your work by line-integrating the new E vector along its new zig-zag path to verify that the potential difference between the plates is the same along this new path as it is along a path well beyond, and outside, the dielectric?
 
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FAQ: Dielectric interface plate capacitor at angle alpha

1. What is a dielectric interface plate capacitor at angle alpha?

A dielectric interface plate capacitor at angle alpha is a type of capacitor that consists of two conducting plates separated by a dielectric material at an angle alpha. This angle is measured between the normal of the plates and the direction of the electric field.

2. What is the purpose of using an angle alpha in a dielectric interface plate capacitor?

The angle alpha in a dielectric interface plate capacitor allows for a non-uniform electric field to be created between the plates. This can be useful in applications where a specific electric field distribution is required.

3. How does the angle alpha affect the capacitance of a dielectric interface plate capacitor?

The angle alpha directly affects the capacitance of a dielectric interface plate capacitor. As the angle increases, the capacitance decreases due to a decrease in the electric field strength between the plates. This relationship is described by the capacitance formula C = εA/d, where ε is the permittivity of the dielectric material, A is the area of the plates, and d is the distance between them.

4. What are some common applications of dielectric interface plate capacitors at angle alpha?

Dielectric interface plate capacitors at angle alpha are commonly used in devices such as electronic filters, sensors, and actuators. They can also be found in various medical equipment, telecommunications systems, and power electronics.

5. How is the electric field distribution affected by changing the angle alpha in a dielectric interface plate capacitor?

Changing the angle alpha in a dielectric interface plate capacitor will result in a change in the electric field distribution between the plates. As the angle increases, the electric field becomes more non-uniform, with a higher concentration of electric field lines near the edges of the plates. This can be visualized using electric field line diagrams.

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