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- Homework Statement
- Consider a plate capacitor with a dielectric interface (\epsilon = \epsilon_0*\epsilon_r, thickness=d) tilted at the angle \alpha . Outside the interface \epsilon = \epsilon_0. Without dielectric interface is the field \vec{E}=E_0*\vec{e_z}. Determine the E-field inside and outside the dielectric interface at the angle \alpha.

- Homework Equations
- E_1*sin a_1= E_2* sin a_2

Consider a plate capacitor with a dielectric interface (\epsilon = \epsilon_0*\epsilon_r, thickness=d) tilted at the angle \alpha . Outside the interface \epsilon = \epsilon_0. Without dielectric interface is the field \vec{E}=E_0*\vec{e_z}.

Determine the E-field inside and outside the dielectric interface at the angle \alpha (a).

My first attempt was to determine the E-field for the parallel and the perpendicular component at the angle \alpha=0 inside and outside the medium.

Inside the medium:

for the parallel component→

**E**_1*sin a_1=

**E**_2* sin a_2 with a_1 = 0 →

**E**_2=a_2=0

So inside the dielectric interface the parallel component is zero

for the perpendicular component: epsilon_1*

**E**_1*cos a_1 = epsilon_2*

**E**_2*cos a_2 with a_1= 0 →

**E**_2=epsilon_1/epsilon_2*

**E**_1

Outside the medium the electric displacement field

**D**represents how an electric field

**E**influences the organization of electric charges in a given medium. In electric field is

**D =**epsilon_0*

**E +P.**

But how do I determine the field for any other angle alpha ? Could I use the equations from the first attempt with a_1≠0 ?