Difference between dS and ds̄

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SUMMARY

The discussion clarifies the distinction between "dS" and "ds̄" in the context of differential calculus. "dS" represents a vector increment of a vector S, while "ds̄" denotes a scalar quantity derived from the dot product of two vectors. Specifically, dS is associated with a vector's direction and magnitude, expressed as dS = |dS| * n, where n is the unit vector. Understanding this difference is crucial for correctly applying these concepts in mathematical theorems and physics.

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Difference between "dS" and "ds̄"

http://img268.imageshack.us/img268/126/skjermbilde20111201kl71.png

I often see theorems such as the one above in my coursework, but I do not actually understand the difference between "dS" and "ds̄". I presume, because the latter has a "hat," that the latter also has something to do with vectors. So what's the difference between these two differential distances?
 
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TranscendArcu said:
http://img268.imageshack.us/img268/126/skjermbilde20111201kl71.png

I often see theorems such as the one above in my coursework, but I do not actually understand the difference between "dS" and "ds̄". I presume, because the latter has a "hat," that the latter also has something to do with vectors. So what's the difference between these two differential distances?
The dS on the left is a vector, an increment of some vector S (looks sort of like the integral for work). The one on the right has dS as a scalar. The integrand here is the dot product of two vectors, which results in a scalar.
 
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Mark44 said:
The dS on the left is a vector, an increment of some vector S (looks sort of like the integral for work). The one on the right has dS as a scalar. The integrand here is the dot product of two vectors, which results in a scalar.

[itex]d\vec{S}[/itex] is the vector whose direction is [itex]\vec{n}[/itex] and whose magnitude is [itex]dS[/itex], so, in fact, we have [tex]d\vec{S} = \vec{n} dS.[/tex]

RGV
 

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