Difference between these equations?

[STEMucator]

I've been curious about this for awhile. What's the difference between the following two equations:

$(1) v_2 = v_1 + a \Delta t$

$(2) v_2^2 = v_1^2 + 2a \Delta d$

My hunch is that $(1)$ represents the final speed in a non-parabolic scenario while $(2)$ is used when the object travels in an arc.

I was curious about this because the two equations won't produce the same answer when asked to find the "final velocity" of an object.

 

[adjacent]

$(1) v_2 = v_1 + a \Delta t$

$(2) v_2^2 = v_1^2 + 2a \Delta d$

2 is used when an object travels in a straight line.Let's put it this way
$v=u+at$
$v^2=u^2+2as$ (v= final velocity,u = initial velocity)
First equation is just a rearrange of acceleration equation which is
$a=\frac{v-u}{t}$
The second equation is formed by combining the equations
$s=\frac{1}{2}(u+v)t$ and $v=u+at$ (First equation)
These equations are known as Equations of motion.
Each equation has one quantity absent,in equation 1,it's s
In equation 2,It's t.

Yes,the two equations looks similar,because it's subject is v.However,two equations have different quantities.

If for example,u= 0. v= 10m/s .a= 2
Then time taken is 5 sec
and distance traveled is 25m.
What's the problem in this?Does this look similar?Does distance and time look similar?Note:s is displacement,v and u is velocity.They are not distance and speed
All the equations of motion applies if acceleration is uniform and object move in a straight line

 

[dauto]

I've been curious about this for awhile. What's the difference between the following two equations:

$(1) v_2 = v_1 + a \Delta t$

$(2) v_2^2 = v_1^2 + 2a \Delta d$

My hunch is that $(1)$ represents the final speed in a non-parabolic scenario while $(2)$ is used when the object travels in an arc.

I was curious about this because the two equations won't produce the same answer when asked to find the "final velocity" of an object.

But they do produce the same answer and they both apply to uniformly accelerated motion.