Difference between X and Amplitude (Simple Harmonic Motion)?

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The discussion focuses on the relationship between displacement (X) and amplitude in the context of simple harmonic motion. The equation V=Vo √1-(x^2/a^2) describes the speed of an object attached to a spring as a function of its displacement. To find amplitude, one must consider the maximum displacement where speed is zero. This leads to a straightforward equation for determining amplitude from the given formula. Understanding this relationship is essential for beginners in physics.
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V=Vo √1-(x^2/a^2)

X is the distance of the spring's stretch, but how would you rearrange the equation if you are looking for Amplitude? They both use the same units (meters) as far as I am concerned. Help would be appreciated, thanks; I am still a beginner with Physics.
 
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I'm guessing that this is the formula for the speed of the object attached to the spring as a function of the displacement ##x##. The amplitude is the maximum value of the displacement, so you should ask what the value of the speed is when the object is at the maximum displacement. That should lead to an easy to solve equation for the maximum displacement.
 

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