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## Homework Statement

The horizontal pipe, shown in the figure, has a cross-sectional area of [itex]40,0 cm^{2}[/itex] at the wider portions and [itex]10,0 cm^{2}[/itex] at the constriction. Water is flowing in the pipe, and the discharge from the pipe is [itex]6,00*10^{-3}\frac{m^{3}}{s} (6,00\frac{L}{s})[/itex]. The density of mercury is [itex]\rho_{Hg}=13,6*10^{3}\frac{kg}{m^{3}}[/itex] and the density of water is [itex]\rho_{w}=1,00*10^{3}\frac{kg}{m^{3}}[/itex].

What is the difference in height between the mercury columns in the U-shaped tube?

## Homework Equations

I've been using Bernoulli's Principle.

[itex]P_{1}+\rho*g*H_{1}=P_{2}+\rho*g*H_{2}[/itex]

## The Attempt at a Solution

When I use the formula above I get 0.127 m which is incorrect. I also found this problem on the internet where they get the same answer so I was pretty sure but apparently it's wrong. :(

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