Differences between equations of SHM

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The discussion centers on the distinction between the sine and cosine functions in the equations for simple harmonic motion (SHM) and circular motion. The sine function, y = A sin(ωt + φ), and the cosine function, x = A cos(ωt + φ), represent two components that are out of phase by π/2, which is essential for describing circular motion. This phase difference corresponds to different initial conditions, affecting the starting position of the oscillating particle. Both functions are solutions to the same differential equation, with the second derivative of sine resulting in negative cosine, reinforcing their relationship in SHM. Ultimately, the choice of sine or cosine is interchangeable through phase shifts, but they represent distinct axes in the motion.
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Why is it that ## y = A\sin (\omega t + \phi) ## whereas ## x = A\cos (\omega t + \phi) ##?

Why is it that the y function is a sine wave, whereas the x function a cosine wave? I'm sorry if this question sounds ridiculous.
 
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is this circular motion? for SHM it doesn't matter if you use cosine or sine. for circular motion it's because the two components have to be out of phase. if you used both cosine or both sine, then the particle would oscillate back and forth on the line y=x
 
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castor said:
Why is it that y=Asin(ωt+ϕ)
because y'' = acceleration and for SHM i needs to be directly proportional to -y(displacement)
and it happens to be that second derivative of sine is ''-''cosine !
otherwise both equations are fundamentally correct
 
If you plot the 2 solutions you will see that they differ by a phase of pi / 2 . This corresponds to a difference in starting position, or the location of the "bob" when you start the clock. So mathematically these are 2 solutions to the same differential equation resulting from different initial conditions.
 
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Shreyas Samudra said:
because y'' = acceleration and for SHM i needs to be directly proportional to -y(displacement)
and it happens to be that second derivative of sine is ''-''cosine !
otherwise both equations are fundamentally correct

The same can be said for the x function; x" = - acceleration, isn't it?

## x = A\cos (\omega t + \phi) ##
## x' = - A\omega\sin (\omega t + \phi) ##
## x'' = - A\omega^2\cos (\omega t + \phi) ##
## x'' = - \omega^2 (A\cos (\omega t + \phi)) ##
## x'' = - \omega^2 x ##

No, the only thing I'm asking is that why is the y function a sine wave, and the x component a cosine wave? Is it, as Integral said, just an example of the two functions having two initial conditions that have a phase difference of ##\frac{\pi}{2}##?
 
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castor said:
Why is it that y=Asin(ωt+ϕ) y = A\sin (\omega t + \phi) whereas x=Acos(ωt+ϕ) x = A\cos (\omega t + \phi) ?

There is no relation between the two equations - first is along y-axis direction and other along x-axis .

If your question is why one uses cosine and other sine , the cos and sin are interchangeable due to the phase φ by + - π/2 ( changing φ at the same time ) .
 
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Qwertywerty said:
There is no relation between the two equations - first is along y-axis direction and other along x-axis .

If your question is why one uses cosine and other sine , the cos and sin are interchangeable due to the phase φ by + - π/2 ( changing φ at the same time ) .
Right, thanks for clearing that up! :)
 

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