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helpmeppl
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1. function is x^2 if x is rational 0 if x is irrational. I need to prove that function is only differentiable at 0.
2. f'(x)=lim(h->0)=(f(x+h)-f(x))/h
3. fruitless attempt-----> So f'(0)=lim(h->0) f(h)/h=lim(h->0)x since it's 0 when irrational and x when rational, 0 when irrational, x=0. thanks.
2. f'(x)=lim(h->0)=(f(x+h)-f(x))/h
3. fruitless attempt-----> So f'(0)=lim(h->0) f(h)/h=lim(h->0)x since it's 0 when irrational and x when rational, 0 when irrational, x=0. thanks.
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