Differentiable off and even functions

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SUMMARY

The discussion focuses on proving that the derivative of a differentiable even function, denoted as f', is an odd function, while the derivative of a differentiable odd function is an even function. The key approach involves using the definitions of even and odd functions, specifically proving f'(-x) = -f'(x) for even functions and f'(-x) = f'(x) for odd functions. Participants emphasize the importance of applying the chain rule and the difference quotient in these proofs.

PREREQUISITES
  • Understanding of even and odd functions in calculus
  • Familiarity with the concept of derivatives
  • Knowledge of the chain rule in differentiation
  • Experience with the difference quotient method
NEXT STEPS
  • Study the properties of even and odd functions in depth
  • Learn how to apply the chain rule in various differentiation scenarios
  • Explore the difference quotient method for calculating derivatives
  • Practice proving properties of derivatives for different types of functions
USEFUL FOR

Students studying calculus, particularly those focusing on differentiation and function properties, as well as educators seeking to enhance their teaching of these concepts.

tsang
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Homework Statement


Let f: R\rightarrow R be a differentiable even function. Prove that f' is an odd
function.
Also, prove that if f is a differentiable odd function, then f' is an even function.


Homework Equations





The Attempt at a Solution


I tried to use definition, so I should tried to prove f'(-x)=-f'(x) for first part, and f'(-x)=f'(x) for second part, but I cannot end up these results.
 
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Why don't you show us what you did? It might help to change h to -h in the limit definition
 
Are you using the difference quotient? You should be able to do this by differentiating f'(-x), letting u= -x and using the chain rule.
 

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