Differential calcuals basic first year

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SUMMARY

The discussion focuses on finding the derivative dy/dx for the implicit equation x^2 y - x = y^3. The solution involves applying the power rule, product rule, and chain rule to differentiate both sides of the equation. The final expression for dy/dx is correctly derived as (2xy - 1) / (x^2 - 3y^2). However, a participant points out an algebraic error in the third step regarding the sign of the term when moving it across the equation.

PREREQUISITES
  • Understanding of implicit differentiation
  • Familiarity with the power rule in calculus
  • Knowledge of the product rule for derivatives
  • Ability to apply the chain rule in differentiation
NEXT STEPS
  • Review implicit differentiation techniques
  • Practice problems involving the power rule and product rule
  • Explore advanced applications of the chain rule
  • Learn how to format mathematical expressions using LaTeX
USEFUL FOR

First-year calculus students, educators teaching differential calculus, and anyone seeking to improve their skills in implicit differentiation and algebraic manipulation.

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Homework Statement


find dy/dx x^2 y-x=y^3


Homework Equations


Power rule, Product rule, chain rule, General power rule


The Attempt at a Solution



2xy+x^2 dy/dx -1=3y^2 dy/dx ( took the derivative of both sides)

2xy+x^2 dy/dx -1-3y^2 dy/dx=0 ( Subtracted the right side)

dy/dx(x^2-3y^2)=2xy-1 ( took out dy/dx)

dy/dx=2xy-1 / (x^2-3y^2) ( final answer)


Is this correct?

It looks much nicer on word
 
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It would look much nicer in TeX too. But what you have is fine. Your algebra failed you in the third step. You are off by a '-' sign. How did 2xy-1 just move over to the right side?
 

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