Differential Calculus - Question

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SUMMARY

The discussion focuses on the simplification of the expression \(\frac{1}{(2x+1)^{1/2}}-\frac{1}{(2x+1)^{3/2}}\) into \(\frac{2x}{(2x+1)^{3/2}}\) using the common denominator method. The common denominator is established as \((2x+1)^{3/2}\), achieved by multiplying the numerator and denominator of the first fraction by \((2x+1)\). This foundational rule of adding and subtracting fractions is essential for understanding differential calculus operations involving rational expressions.

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Homework Statement



I don't understand how this can be written like this:

[tex]\frac{1}{(2x+1)^{1/2}}-\frac{1}{(2x+1)^{3/2}}=\frac{2x+1-1}{(2x+1)^{3/2}}=\frac{2x}{(2x+1)^{3/2}}[/tex]


What's the rule which makes this possible and explain please.
 
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The "rule" is one that you probably learned in the third grade: you add or subtract fractions by getting a "common denominator".

The first fraction has denominator [itex](2x+1)^{1/2}[/itex]. The second fraction has denominator [itex](2x+ 1)^{3/2}= (2x+1)^{1+ 1/2}= (2x+1)(2x+1)^{1/2}[/itex].

In other words, the common denominator is [itex](2x+1)^{3/2}[/itex] and you get it by multiplying the numerator and denominator of the first fraction by 2x+1.
 

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