Differential Equation, Frobenius method

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Homework Help Overview

The problem involves finding two linearly independent power series solutions for the differential equation xy" - y' + xy = 0 using the Frobenius method. The context is centered around differential equations and series solutions.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to solve for the indicial roots and expresses uncertainty about the correctness of their results, particularly regarding a zero in the denominator. Other participants suggest checking the textbook for similar cases and discuss the implications of having indicial roots that differ by an integer.

Discussion Status

Participants are exploring different aspects of the Frobenius method, including the need for additional transition equations and the implications of the indicial roots. Some guidance has been offered regarding the use of reduction of order and the structure of the general solution, but there is no explicit consensus on the next steps.

Contextual Notes

There are mentions of complications arising from the presence of both roots when r=2, and the original poster notes confusion about how this affects their solutions. The discussion includes references to specific terms in the Frobenius series and the need for careful manipulation of indices.

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Homework Statement



Find two linearly independent power series solutions for xy" - y' + xy = 0 using the Frobenius method.

Homework Equations



gif.latex?\sum_{n=0}^{\infty%20}c_{n}x^{n+r}.gif


The Attempt at a Solution



solving for the indicial roots I got:

gif.gif

-> r(r-2) = 0
r = 0, 2

for the recursion formula I got:

gif.gif


gif.gif


I'm not completely sure this is correct, but if it is, I don't know where to go from here. I have a 0 in the denominator for the first few solutions when r=0. What am I doing wrong?

Thanks.
 
Last edited:
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Check your textbook. Your solutions to the indicial equation differ by an integer. That case is similar to the situation in the "Euler-Cauchy" equation when you have a double root to the characteristice equation- you have to multiply by ln(x).
 
As HallsofIvy has pointed out, the two solutions to the indicial equation differ by an integer. This means that the only guaranteed solution is obtained by using the greater value of the two solutions - to get the other linearly independent solution to your homogeneous equation, you can use reduction of order; assume that the general solution looks like

y(x) = A(x) y_1(x),​

where y_1(x) is the solution you obtain from the greater value of the indicial equation. Differentiating this and plugging into your ODE will yield a first-order linear equation, after redefining a variable.

Hope this helps. :)
 
Thanks, trying it now but I have another question.

All of the examples have only
gif.gif
values when finding solutions, but mine have both
gif.gif
and
gif.gif
when r=2. Should this be happening? When I try to use it these solutions to find my second solution it seems to mess everything up.

This is what I got for my first solution-

%20c_{1}[x%20-%20\frac{1}{3\cdot%205}x^{3}%20+%20\frac{1}{3\cdot%205^{2}\cdot%207}x^{5}%20+%20...gif
 
Last edited:
For some Frobenius series expansions, in addition to the indicial equation, additional transition equations may appear that allow you to determine the c_i, where i is some number in \mathbb{N}. In this example, you should have an additional transition equation to determine c_1, and the final Frobenius series is left as a function of c_0. What you have to do is write out the the first two terms of the Frobenius expansion explicitly and then group the remaining terms into one single infinite series (by doing some index manipulation acrobatics). The first two terms give, respectively, the indicial equation (which you apparently already have) and the equation to determine c_1. Don't hesitate to ask if you get stuck somewhere. :)
 
I think I got it now, thanks :smile:
 

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