- #1
mrmotobiker
- 48
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Homework Statement
i'm stuck. could someone please help me with this? thanks!
find the general solution:
y''+2y'+y=2e^-t
Homework Equations
CE: r^2+2r+1=0
(r+1)^2 which means r1=r2=-1
c1e^-t+c2te^-t
The Attempt at a Solution
Y(t)=Ae^-t
Y'(t)=-Ae^-t
Y''(t)=Ae^-t
back into the equation:
Ae^-t-2Ae^-t+Ae^-t=2Ae^-t
0=Ae^-t
now im stuck! what am i doing wrong?! this is the "easiest" problem! isn't the A left there and that's how i find the GS?
the answer is supposed to be c1e^-t+c2tAe^-t+t^2Ae^-t