- #1

mrmotobiker

- 48

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## Homework Statement

i'm stuck. could someone please help me with this? thanks!

find the general solution:

y''+2y'+y=2e^-t

## Homework Equations

CE: r^2+2r+1=0

(r+1)^2 which means r1=r2=-1

c1e^-t+c2te^-t

## The Attempt at a Solution

Y(t)=Ae^-t

Y'(t)=-Ae^-t

Y''(t)=Ae^-t

back into the equation:

Ae^-t-2Ae^-t+Ae^-t=2Ae^-t

0=Ae^-t

now im stuck! what am i doing wrong?! this is the "easiest" problem! isn't the A left there and that's how i find the GS?

the answer is supposed to be c1e^-t+c2tAe^-t+t^2Ae^-t