Differential equation what going on?

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Discussion Overview

The discussion revolves around the solution to the differential equation dx/dt = xt, focusing on the steps involved in integrating and rearranging the equation to derive the expression for x. Participants seek clarification on the manipulation of logarithmic and exponential functions during the solution process.

Discussion Character

  • Exploratory, Technical explanation, Homework-related

Main Points Raised

  • James expresses confusion about the integration process and how the result x = Ce^(t^2/2) is derived from In(x) = t^2/2 + c.
  • One participant notes that exponentiating both sides leads to the solution, emphasizing the inverse relationship between exponential functions and logarithms.
  • James questions the form of the constant C in relation to the exponent, seeking clarification on the rules of exponentials.
  • Another participant corrects James, suggesting that the correct form should be x = Ce^(t^2/2) instead of x = Ce^(2/t^2).
  • A different participant provides a detailed breakdown of the integration steps, introducing a constant K and relating it to C, which helps clarify the manipulation of the equation.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the exact form of the solution, with some variations in the expressions presented. However, there is general agreement on the method of exponentiation and the relationship between logarithmic and exponential functions.

Contextual Notes

Some assumptions regarding the constants and the manipulation of the exponential function remain implicit, and the discussion does not resolve all uncertainties about the integration steps.

Who May Find This Useful

Students or individuals studying differential equations, particularly those struggling with integration techniques and the properties of logarithmic and exponential functions.

jamesd2008
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Hi could someone explain why this result occurs when solving this differential equation.

dx/dt= xt

1/xdx/dt=t then intergrating both side we get with respect to dt we get,

Inx=t^2/2 + c now this is the bit i don't understand why does the answer then become,

x=Ce^2/t^2

I get really confused how the equation gets re-arranged into the above form after the intergration has occurred. Any help please?

Thanks
James
 
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jamesd2008 said:
Inx=t^2/2 + c now this is the bit i don't understand why does the answer then become,

x=Ce^2/t^2

I get really confused how the equation gets re-arranged into the above form after the intergration has occurred. Any help please?

Thanks
James
You are just exponentiating both sides of the equation. But remember that exponential functions and log's are inverse functions so e^lnx=x
 
Thanks but how come it is c*the e and then raised to the power of 2/t^2. Is that just a rule of exponentials?
Please help doing my head in!

Thanks
James
 
jamesd2008 said:
Inx=t^2/2 + c now this is the bit i don't understand why does the answer then become,

x=Ce^2/t^2

Hi James! :smile:

No, x = Cet2/2

C is ec. :wink:
 
Hey James
dx/dt= xt
dx/x = t·dt
Ln(x) = (t^2)/2 + K
x=e t2 /2 +K = e K · e t2 /2
If we say that e^K = C then;
x= C·e t2 /2

I hope it helps
 
Thanks all for your help got it now! thanks again james : -)
 

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