Differential equation with sphere

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Homework Help Overview

The problem involves the evaporation of a spherical mothball, where the rate of change of its radius is said to be proportional to its surface area. The original radius is given as 1.2 cm, and after 180 days, the radius decreases to 1 cm. The tasks include determining the time required for the radius to shrink to 25% of its original size and for the volume to reduce to half of its original value.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the initial equation for the rate of evaporation and question its validity, particularly the assumption that the rate is proportional to the surface area. There are attempts to derive expressions for time based on the given conditions, but concerns about calculation errors are raised.

Discussion Status

The discussion is ongoing, with some participants suggesting that the original poster may have made calculation errors in their final results. There is also a realization about the time units being in days rather than years, which has led to a correction in understanding.

Contextual Notes

Participants note the importance of the initial conditions and the physical assumptions regarding the evaporation process, which may not align with typical expectations.

dinospamoni
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Homework Statement



A spherical mothball of original radius 1.2 cm slowly
evaporates such that 180 days later, its radius is only 1 cm.
Physically, the rate of evaporation dr/dt is proportional to the
surface area of the sphere. Determine a) the time required for
the radius of a new mothball to shrink to 25 percent of its
original radius, and b) the time required for the volume of a
new mothball to become half of its original value.

Homework Equations



SA= 4 pi r^2
r(0)=1.2
r(180)=1

The Attempt at a Solution



I started by saying -dr/dt = c1 4 pi r^2

where c1 is a constant of proportionality

Then through separation of variables I found that

1/r = 4 pi c1 t + c2

after imposing the initial conditions I found c1=7.383*10^-5 and c2=.833

so I have

1/r = 4 pi (7.383*10^-5) t + .833

and this gives me answers of
1) 2694 yr
2) 233.82 yr

but these aren't right. Any ideas of where I went wrong?
 
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Your equation give the right values for t=0 and t=180, so I think you have some calculation error in the final steps.

I seriously doubt that mothballs evaporate like that. It would mean that evaporation is proportional to the square of the surface area.
 
Yeah, I think I might have the wrong initial equation, but I'm not sure of what it could be
 
dinospamoni said:

Homework Statement



A spherical mothball of original radius 1.2 cm slowly
evaporates such that 180 days later, its radius is only 1 cm.
Physically, the rate of evaporation dr/dt is proportional to the
surface area of the sphere. Determine a) the time required for
the radius of a new mothball to shrink to 25 percent of its
original radius, and b) the time required for the volume of a
new mothball to become half of its original value.

Homework Equations



SA= 4 pi r^2
r(0)=1.2
r(180)=1

The Attempt at a Solution



I started by saying -dr/dt = c1 4 pi r^2

where c1 is a constant of proportionality

Then through separation of variables I found that

1/r = 4 pi c1 t + c2

after imposing the initial conditions I found c1=7.383*10^-5 and c2=.833

so I have

1/r = 4 pi (7.383*10^-5) t + .833

and this gives me answers of
1) 2694 yr
2) 233.82 yr

but these aren't right. Any ideas of where I went wrong?

1/r = 4 pi (7.383*10^-5) t + .833 looks ok. Why are you giving the times in yrs? Don't you mean days? And I'd check those again.
 
Dick said:
1/r = 4 pi (7.383*10^-5) t + .833 looks ok. Why are you giving the times in yrs? Don't you mean days? And I'd check those again.

Wow. Don't I feel silly. I was working on several problems at once and I guess I forgot this one was in days, not years and it worked. Good eye! Also, Thanks a ton!
 

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