Differential equation with sphere

In summary: Your equation give the right values for t=0 and t=180, so I think you have some calculation error in the final steps.I seriously doubt that mothballs evaporate like that. It would mean that evaporation is proportional to the square of the surface area.Yeah, I think I might have the wrong initial equation, but I'm not sure of what it could be. After further research, it seems like the correct equation would be:dV/dt = -k * 4πr^2where k is a constant representing the rate of evaporation. This would lead to a different equation and values for t, but the methodology would remain the same.
  • #1
dinospamoni
92
0

Homework Statement



A spherical mothball of original radius 1.2 cm slowly
evaporates such that 180 days later, its radius is only 1 cm.
Physically, the rate of evaporation dr/dt is proportional to the
surface area of the sphere. Determine a) the time required for
the radius of a new mothball to shrink to 25 percent of its
original radius, and b) the time required for the volume of a
new mothball to become half of its original value.

Homework Equations



SA= 4 pi r^2
r(0)=1.2
r(180)=1

The Attempt at a Solution



I started by saying -dr/dt = c1 4 pi r^2

where c1 is a constant of proportionality

Then through separation of variables I found that

1/r = 4 pi c1 t + c2

after imposing the initial conditions I found c1=7.383*10^-5 and c2=.833

so I have

1/r = 4 pi (7.383*10^-5) t + .833

and this gives me answers of
1) 2694 yr
2) 233.82 yr

but these aren't right. Any ideas of where I went wrong?
 
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  • #2
Your equation give the right values for t=0 and t=180, so I think you have some calculation error in the final steps.

I seriously doubt that mothballs evaporate like that. It would mean that evaporation is proportional to the square of the surface area.
 
  • #3
Yeah, I think I might have the wrong initial equation, but I'm not sure of what it could be
 
  • #4
dinospamoni said:

Homework Statement



A spherical mothball of original radius 1.2 cm slowly
evaporates such that 180 days later, its radius is only 1 cm.
Physically, the rate of evaporation dr/dt is proportional to the
surface area of the sphere. Determine a) the time required for
the radius of a new mothball to shrink to 25 percent of its
original radius, and b) the time required for the volume of a
new mothball to become half of its original value.

Homework Equations



SA= 4 pi r^2
r(0)=1.2
r(180)=1

The Attempt at a Solution



I started by saying -dr/dt = c1 4 pi r^2

where c1 is a constant of proportionality

Then through separation of variables I found that

1/r = 4 pi c1 t + c2

after imposing the initial conditions I found c1=7.383*10^-5 and c2=.833

so I have

1/r = 4 pi (7.383*10^-5) t + .833

and this gives me answers of
1) 2694 yr
2) 233.82 yr

but these aren't right. Any ideas of where I went wrong?

1/r = 4 pi (7.383*10^-5) t + .833 looks ok. Why are you giving the times in yrs? Don't you mean days? And I'd check those again.
 
  • #5
Dick said:
1/r = 4 pi (7.383*10^-5) t + .833 looks ok. Why are you giving the times in yrs? Don't you mean days? And I'd check those again.

Wow. Don't I feel silly. I was working on several problems at once and I guess I forgot this one was in days, not years and it worked. Good eye! Also, Thanks a ton!
 

1. What is a differential equation with a sphere?

A differential equation with a sphere is a mathematical equation that involves the derivatives of a function and is defined on a sphere. It is used to describe physical phenomena such as heat transfer, fluid flow, and wave propagation.

2. How is a differential equation with a sphere different from a regular differential equation?

A differential equation with a sphere is different because it is defined on a curved surface, whereas a regular differential equation is defined on a flat surface. This adds an extra level of complexity to the equation and requires specialized techniques to solve it.

3. What are some applications of differential equations with spheres?

Differential equations with spheres have many applications in physics, engineering, and other areas of science. They are used to model the behavior of physical systems such as atmospheric circulation, ocean currents, and heat transfer in the Earth's interior.

4. What are some techniques for solving differential equations with spheres?

There are several techniques for solving differential equations with spheres, including separation of variables, Laplace transform, and Green's function method. Each technique has its own advantages and is used depending on the specific problem at hand.

5. What are some challenges in solving differential equations with spheres?

Solving differential equations with spheres can be challenging due to the complex geometry of the sphere and the nonlinearity of the equations. In addition, there may not always be an analytical solution, so numerical methods may need to be used. It also requires a strong understanding of mathematical concepts and techniques.

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