- #1
theown1
- 13
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Homework Statement
(b) Find the differential equation for which –4xy3 + 4xy3sin(x) = –1 is an implicit solution on the interval (0, pi/2). Write your answer in the form dy/dx = f (x,y) where f (x, y) depends on both x and y.
The Attempt at a Solution
I'm not too sure on how to go about solving for the differential equation after been given the implicit form. So farI got
dy/dx= cos(x)-4/(-3y3)
which I don't think is right, and
I'm not sure where to start?
(4xy3)(sin(x)-1)=-1
4y3=-1/[x(sin(x)-1]
and then do I take the derivative of this ^ to get my answer?