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## Homework Statement

Suppose that the initial value problem

y' = 7(x^2) + (5y^2) − 6, y(0)=−2

has a solution in an interval about x=0.

Find y'(0) =

Find y''(0) =

Find y'''(0) =

## Homework Equations

get it into standard form: dy/dt + p(t)y = g(t)

find integrating factor = e^([tex]\int[/tex]p(t)dt + k

multiply everything by integrating factor, simplify left-hand-side and then integrate both sides

using initial condition, solve for C

solve for y

## The Attempt at a Solution

i don't seem to be able to get it into standard form

i tried doing y' - 5y^2 = 7x^2 -6

which gave me an integrating factor of e^-5xy

i tried following the rest of the steps with that integrating factor but its not working