Differential Equations - power series method

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SUMMARY

The discussion focuses on solving the differential equation y'' + y' - 2y = 0 using the power series method. The initial conditions provided are y(0) = 1 and y'(0) = -2. The user successfully derives the recurrence relation and confirms that c0 = 1 and c1 = -2 are valid assumptions, leading to the solution y(x) = e^(-2x). This demonstrates the application of power series in solving linear differential equations.

PREREQUISITES
  • Understanding of differential equations, specifically second-order linear equations.
  • Familiarity with power series expansions and their convergence.
  • Knowledge of initial value problems and how to apply initial conditions.
  • Basic calculus, particularly differentiation and series manipulation.
NEXT STEPS
  • Study the method of power series solutions for differential equations in greater detail.
  • Explore the concept of recurrence relations in the context of series solutions.
  • Learn about the applications of the exponential function in solving differential equations.
  • Investigate other methods for solving second-order linear differential equations, such as the Laplace transform.
USEFUL FOR

Students studying differential equations, educators teaching advanced calculus, and anyone interested in mathematical methods for solving linear differential equations.

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Homework Statement



Solve:

y'' + y' - 2y = 0

y(0) = 1
y'(0) = -2

Homework Equations





The Attempt at a Solution



I found:

http://image.cramster.com/answer-board/image/cramster-equation-200942414569633761817696516250247.gif

So the recurrence relation is:

http://image.cramster.com/answer-board/image/cramster-equation-20094241457286337618184812037502167.gif

for n = 0:

http://image.cramster.com/answer-board/image/cramster-equation-20094241458446337618192469850005024.gif

Now here's my question. Can I assume at this point that:

c0 = y(0) = 1
and c1 = y ' (0) = -2

?

This would allow me to have a numerical value for each cn.

Thanks!
 
Last edited by a moderator:
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Yes. Think about what your original power series for y(x) looked like. All the terms except the first had nonzero powers of x, so if x = 0, you have y(0) = c0. Then, think about what y'(x) looks like. Same idea for c1.
 
Thanks Mark. I was able to solve this by making the above assumption getting y(x) = e-2x I just wasn't sure if I was permitted to make that assumption.
 

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