Differential equations power series method

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SUMMARY

The discussion focuses on solving the differential equation y' + t^3y = 0 using the power series method centered at t=0. The user derived the recurrence relation a_n = -a_{n-4}/n for n ≥ 4 but was confused about handling the initial terms a_1, a_2, and a_3. It was clarified that these terms should be set to zero, leading to a solution where only terms for n=0, 4, 8, etc., remain non-zero. The equation is also noted to be separable, allowing for a closed-form solution.

PREREQUISITES
  • Understanding of power series representation of functions
  • Familiarity with differential equations, specifically first-order linear equations
  • Knowledge of recurrence relations in series solutions
  • Basic calculus, including differentiation and summation
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  • Study the method of solving differential equations using power series
  • Learn about recurrence relations and their applications in series solutions
  • Explore the concept of separable differential equations and their solutions
  • Investigate the implications of initial conditions in power series expansions
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Students and educators in mathematics, particularly those studying differential equations and series solutions, as well as anyone looking to deepen their understanding of power series methods in solving ODEs.

SpiffyEh
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Homework Statement



using the power series method (centered at t=0) y'+t^3y = 0 find the recurrence relation

Homework Equations



y= \sum a_{n}t^{n} from n=0 to infinity
y'= \sum na_{n}t^{n-1} from n=1 to infinity

The Attempt at a Solution


I went through and solved by putting the values from b into the equation and i got down to this:
a_{1}+2a_{2}t+3a_{3}t^{2}+\sum[na_{n}+a_{n-4}]t^{n-1} = 0

the 1 2 and 3 should be subscripted on a

I understand how to get an which i think i got right... i got a_{n} = -a_{n-4}/n whre n >= 4

But I don't understand what i do with the other part.. the a_{1}+2a_{2}t+3a_{3}t^{2}
Do i set it to 0 and solve for something? or do i set each individual component to 0. If i do ti this way and i find the power series solution by going through values of n until i find a pattern they all end up being 0 which can't be right. I'm completely lost.

Please let me know, this is due tomorrow and I have everything done except I don't understand what to do with this one. I just need to know what to do with that part, I can do the rest.

Thank you so much
 
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SpiffyEh said:

Homework Statement



using the power series method (centered at t=0) y'+t^3y = 0 find the recurrence relation

Homework Equations



y= \sum a_{n}t^{n} from n=0 to infinity
y'= \sum na_{n}t^{n-1} from n=1 to infinity

The Attempt at a Solution


I went through and solved by putting the values from b into the equation and i got down to this:
a_{1}+2a_{2}t+3a_{3}t^{2}+\sum[na_{n}+a_{n-4}]t^{n-1} = 0

the 1 2 and 3 should be subscripted on a

I understand how to get an which i think i got right... i got a_{n} = -a_{n-4}/n whre n >= 4

But I don't understand what i do with the other part.. the a_{1}+2a_{2}t+3a_{3}t^{2}
Do i set it to 0 and solve for something? or do i set each individual component to 0. If i do ti this way and i find the power series solution by going through values of n until i find a pattern they all end up being 0 which can't be right. I'm completely lost.

Please let me know, this is due tomorrow and I have everything done except I don't understand what to do with this one. I just need to know what to do with that part, I can do the rest.

Thank you so much
You're right. You set the first three terms to zero, so you get a_1=a_2=a_3=0. The only non-zero terms in your power series will therefore be for n=0, 4, 8, ...

This differential equation is separable, so you can find the solution in closed form. Expand it as a series and see if it matches what the series solution seems to be giving you.
 

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