Differential Equations problem

  • #1

Homework Statement


y=sinx cosx -cosx y'+(tanx)y=cos^2 x



I know that I'm supposed to see if the Left hand side equals the Right hand side, but I'm having problems differentiating y=sinx cosx -cosx

Yea believe it or not
 
Last edited:

Answers and Replies

  • #2
1,753
1
[tex]y=\sin x\cos x-\cos x[/tex] is a product

Product rule: [tex](fg)'=fg'+gf'[/tex]
 
  • #3
Thanks
 

Related Threads on Differential Equations problem

  • Last Post
Replies
4
Views
1K
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
1
Views
923
  • Last Post
Replies
4
Views
2K
  • Last Post
Replies
7
Views
1K
  • Last Post
Replies
2
Views
852
  • Last Post
Replies
1
Views
2K
  • Last Post
Replies
1
Views
2K
Replies
1
Views
5K
  • Last Post
Replies
3
Views
3K
Top