Differentiate heavy side function

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SUMMARY

The discussion centers on the differentiability of the Heaviside step function, defined as H(x) = 1 for x ≥ 0 and H(x) = 0 for x < 0. Participants identify that the function is not continuous at x = 0, where it jumps from 0 to 1, and raise questions about its behavior at x = 2. The consensus is that the function is only discontinuous at x = 0, and there is a noted error in the derivative notation for x > 2, which requires correction for clarity.

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  • Understanding of piecewise functions
  • Knowledge of continuity and differentiability concepts
  • Familiarity with the Heaviside step function
  • Basic calculus, specifically derivatives
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  • Study the properties of the Heaviside step function in detail
  • Learn about continuity and differentiability in piecewise functions
  • Explore the concept of limits and their role in determining continuity
  • Review derivative notation and common errors in calculus
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Students studying calculus, particularly those focusing on piecewise functions and their differentiability, as well as educators looking for examples of common misconceptions in calculus.

homo-sapiens
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Homework Statement


find points where function is differentiable
http://puu.sh/cqrc8/f96bd06aee.png

Homework Equations


H(x) = 1, x >= 0
H(x) = 0, x < 0[/B]

The Attempt at a Solution


i Draw a number line and see where the function would change or jump. and immediately i noticed that the function would not be continuous on x=0 and x=2 since that is when the function jumps.
http://puu.sh/cqrBE/44b7fe56ff.png
however i don't see any other discontinuities in the function. if so then what is the last note for? Am i completely missing the point in this question here??[/B]
 
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homo-sapiens said:
the function would not be continuous on x=0 and x=2 since that is when the function jumps.
Does it jump at 2? Btw, in your posted working you left out an x in the exponent of f' for x > 2.
 

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