Differentiating Exponential Functions with Fractional Exponents

  • Thread starter Thread starter afcwestwarrior
  • Start date Start date
  • Tags Tags
    Differentiate
Click For Summary

Homework Help Overview

The discussion revolves around differentiating the function y = e^x / x^2, which involves exponential functions with fractional exponents. Participants are exploring methods for finding the derivative of this expression.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss using the quotient rule and the product rule for differentiation. There are attempts to clarify the expression and its components, with some questioning the setup and notation.

Discussion Status

The discussion is active, with participants offering different methods for differentiation. There is recognition of multiple approaches, but no explicit consensus on a single method has been reached.

Contextual Notes

Some participants express uncertainty about the notation used in the original problem, which may affect clarity. There is also mention of the original poster knowing the answer but seeking understanding of the differentiation process.

afcwestwarrior
Messages
453
Reaction score
0
y=ex(x is suppost to be smaller and on the top right of e)/x squared

i a suppost to differentiate this, well i wrote -2ex/x cubed+ ex/ x sq.

now u probabl might be confused by the way i wrote it since i don't know how to put the right things for my problems,

well i set up the problem how do i figure out the answer,

i know the answer but how do i figure it out
 
Last edited:
Physics news on Phys.org
Is this what you are getting at y = ex/x2?

Would it help if you rewrite it as a product rule:
ex.x-2
 
afcwestwarrior said:
i a suppost to differentiate this, well i wrote -2ex/x cubed+ ex/ x sq.

This is correct.
 
afcwestwarrior said:
i know the answer but how do i figure it out

[tex]y=\frac{e^x}{x^2}[/tex]
Let [itex]u=e^x[/itex] and [itex]v=x^2[/itex].

By the quotient rule, the derivative is [tex]\frac{u'v-v'u}{v^2}[/tex]
 
afcwestwarrior said:
i know the answer but how do i figure it out

I must've skipped over this, and so didn't notice that you wanted to know how to get the answer!

Well, anyway, now you've got two ways; using the product rule as shown by ranger, or the quotient rule given by Gib Z.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 25 ·
Replies
25
Views
2K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
3
Views
2K
Replies
5
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
Replies
2
Views
1K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K