Differentiation and integration

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Homework Help Overview

The discussion revolves around differentiation and integration, specifically the application of a differential operator to an integral involving functions of two variables. The original poster questions the validity of interchanging the order of differentiation and integration in a specific context.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to simplify the expression and explore the implications of the term (x-y) within the integral. Some participants suggest using properties of the Dirac delta function as a potential approach to the problem.

Discussion Status

Participants are exploring the topic with references to general formulas and specific properties of functions involved. There is mention of the Leibniz integral rule, indicating a direction towards established mathematical principles, but no consensus has been reached on the original poster's question.

Contextual Notes

The original poster notes a lack of experience with multivariable calculus, which may influence their understanding of the concepts being discussed. There is also a reference to a theorem that might relate to the problem, although it has not been explicitly identified.

davon806
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Homework Statement


Hi,I saw a statement in my physics notes like this(Anyway it is a maths problem):

diff.png


where L is a general differential operator.G is a green's function(I guess it is irrelevant)
My question is related to the red line:
Suppose we have this:
∂/∂x ∫ f(x-y)g(y) ∂y
is it generally true that
∂/∂x ∫ f(x-y)g(y) ∂y = ∫ ∂/∂x [ f(x-y)g(y) ] ∂y ?

Homework Equations


Please answer it as simply as you can...Since I have not done multivariable calculus...(Though I would be happy to check it out if there is a theorem related to this.)

The Attempt at a Solution


If the above is simplified to ∂/∂x ∫ f(x)g(y) ∂y ,then ∂/∂x [f(x) ∫ g(y) ∂y]
⇒ ∫ ∂/∂x [ f(x) ] g(y) ∂y
⇒ ∫ ∂/∂x [ f(x)g(y) ] ∂y

But I don't know what to do with the (x-y) term..

Thanks
 
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The general formula is:
deaf6cf147e2c72ca92f02fbe5bb17ef.png


But you don't need this. You only need to use the properties of Dirac delta, i.e. ## \int \delta(x-y) f(y) dy=f(x)##.
 
Shyan said:
The general formula is:
deaf6cf147e2c72ca92f02fbe5bb17ef.png


But you don't need this. You only need to use the properties of Dirac delta, i.e. ## \int \delta(x-y) f(y) dy=f(x)##.
Thanks :) Is there a name for this formula?
 

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