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## Homework Statement

Find the derivative of y=(x^2)^sinx; using the chain rule.

## Homework Equations

No other relevant equations.

## The Attempt at a Solution

I attempted to apply the Chain rule: dy/dx = dy/du X du/dx

Subbing u for x^2, which made y = u^sinx

I ended up with du/dx = 2x;

and dy/du = ln(u)*cos(x)*(U)^sinx

I know this isn't right, and all i've spent the past hour doing is confusing myself. I've searched my text book, and online, and can't find anyting (that I understand) to help me.

To be honest, i'm not even sure how i'm supposed to apply the chain rule

Any help would be appreciated, thank you.