Find the derivative of y=(x^2)^sinx; using the chain rule.
No other relevant equations.
The Attempt at a Solution
I attempted to apply the Chain rule: dy/dx = dy/du X du/dx
Subbing u for x^2, which made y = u^sinx
I ended up with du/dx = 2x;
and dy/du = ln(u)*cos(x)*(U)^sinx
I know this isn't right, and all i've spent the past hour doing is confusing myself. I've searched my text book, and online, and can't find anyting (that I understand) to help me.
To be honest, i'm not even sure how i'm supposed to apply the chain rule
Any help would be appreciated, thank you.