Diffraction by single slit - effect of increasing the slit width

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Increasing the slit width in single-slit diffraction narrows the maxima, resulting in a more compact diffraction pattern. Conversely, increasing the wavelength expands the maxima, leading to a wider diffraction pattern. The minima are determined by the formula y = mλD/s, where y is the distance to the m-th minimum, λ is the wavelength, D is the distance to the observation screen, and s is the slit width. Therefore, a larger slit width (D) results in narrower maxima, while a larger wavelength (λ) results in wider maxima. Understanding these effects is crucial for solving diffraction problems in physics.
physicsilliterate
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For diffraction by a single slit, what is the effect of increasing (a) the slit width, and (b) the wavelength? It was a problem on my daughter's final and I never seemed to be able to answer it for her. :confused:
 
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The answer lies in the fact that the minima are located at intervals of n\lambda / D (value of sin)... so a bigger slit (D) makes narower maxima and a larger wavelength (\lambda) makes wider maxima.
 
physicsilliterate said:
For diffraction by a single slit, what is the effect of increasing (a) the slit width, and (b) the wavelength? It was a problem on my daughter's final and I never seemed to be able to answer it for her. :confused:
for single-slit diffraction, the condition for MINIMUMs is:

y \ = \ \frac{m \lambda D}{s}

where y is the distance from central max to the m-th minimum of the diffraction pattern, m a positive integer, λ the wavelength, D the distance between single-slit and distant observation screen where diffraction pattern will be observed, and s the single-slit width. Thus:
a) increasing single-slit width will decrease width of central max ("shrink the diffraction pattern");
b) increasing wavelength will increase width of central max ("expand the diffraction pattern")
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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