Diffraction by single slit - effect of increasing the slit width

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SUMMARY

The discussion focuses on the effects of increasing slit width and wavelength on single-slit diffraction patterns. Increasing the slit width (D) results in narrower maxima, while increasing the wavelength (λ) leads to wider maxima. The minima in the diffraction pattern are determined by the formula y = (mλD)/s, where y is the distance from the central maximum to the m-th minimum, m is a positive integer, and s is the single-slit width. This relationship is crucial for understanding the behavior of light in diffraction scenarios.

PREREQUISITES
  • Understanding of single-slit diffraction principles
  • Familiarity with the formula for minima in diffraction patterns
  • Basic knowledge of wave properties, specifically wavelength
  • Concept of maxima and minima in interference patterns
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  • Study the mathematical derivation of the single-slit diffraction formula
  • Explore the impact of slit width on diffraction patterns using simulation tools
  • Investigate the relationship between wavelength and diffraction in various media
  • Learn about multi-slit interference and its comparison to single-slit diffraction
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physicsilliterate
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For diffraction by a single slit, what is the effect of increasing (a) the slit width, and (b) the wavelength? It was a problem on my daughter's final and I never seemed to be able to answer it for her. :confused:
 
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The answer lies in the fact that the minima are located at intervals of n\lambda / D (value of sin)... so a bigger slit (D) makes narower maxima and a larger wavelength (\lambda) makes wider maxima.
 
physicsilliterate said:
For diffraction by a single slit, what is the effect of increasing (a) the slit width, and (b) the wavelength? It was a problem on my daughter's final and I never seemed to be able to answer it for her. :confused:
for single-slit diffraction, the condition for MINIMUMs is:

y \ = \ \frac{m \lambda D}{s}

where y is the distance from central max to the m-th minimum of the diffraction pattern, m a positive integer, λ the wavelength, D the distance between single-slit and distant observation screen where diffraction pattern will be observed, and s the single-slit width. Thus:
a) increasing single-slit width will decrease width of central max ("shrink the diffraction pattern");
b) increasing wavelength will increase width of central max ("expand the diffraction pattern")
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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