Diffraction Grating - all visible light?

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SUMMARY

The smallest grating spacing required to observe the entire visible spectrum, ranging from 400nm to 700nm, is determined using the diffraction equation nλ = d sin θ. For the first order (n=1), the maximum wavelength observed is 700nm, which corresponds to a grating spacing (d) of 700nm. For the second order (n=2), the maximum wavelength is 1400nm. The maximum angle for observing a wavelength can be calculated using the sine function derived from the diffraction equation.

PREREQUISITES
  • Understanding of the diffraction equation nλ = d sin θ
  • Knowledge of the visible light spectrum (400nm to 700nm)
  • Familiarity with the concept of grating spacing in optics
  • Basic trigonometry for calculating angles
NEXT STEPS
  • Research how to calculate grating spacing for different orders of diffraction
  • Learn about the applications of diffraction gratings in spectroscopy
  • Explore the relationship between wavelength and angle in diffraction patterns
  • Study the effects of varying grating spacing on the visibility of different wavelengths
USEFUL FOR

Students studying optics, physics educators, and anyone interested in the principles of light diffraction and spectroscopy.

clamatoman
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Homework Statement


Find the smallest grating spacing that let's you see the entire visible spectrum.
400nm to 700nm comprises the visible light spectrum.
no other information is given.

Homework Equations


nλ=d sin θ

The Attempt at a Solution


I am not sure how to start as all i have been given is a spectrum of wavelengths...?
 
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Well, apparently its 700nm. And 1400 nm for the second order.
 
What is the maximum angle where a wavelength can be observed?
 

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