Diffraction grating experiment

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Homework Help Overview

The discussion revolves around an experiment involving a red laser passing through a diffraction grating, where measurements are taken to calculate the wavelength of the laser. The original poster reports obtaining two different wavelengths and seeks clarification on how to interpret these results.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to calculate the wavelength using a specific formula and questions whether to average the results or dismiss one as an error. Other participants question the validity of the formula used and suggest a different approach involving the correct trigonometric relationships.

Discussion Status

Participants are actively engaging with the original poster's question, providing guidance on the appropriate formula to use and discussing the implications of the measurements. There is no explicit consensus on how to handle the differing wavelengths, but a productive direction has been provided regarding the correct equation.

Contextual Notes

The discussion highlights potential issues with the assumptions made regarding angle approximations in the calculations, as well as the need for clarity on how to interpret experimental results in the context of error analysis.

m_p_w
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I did an experiment where a red laser went through a diffraction grating
The distance between the diffraction grating to the screen is 10cm (x)
Later I measure the distance from the central dot to the first dot (4.5cm) (y)
after this I measure the distance from the central dot to the second dot(13.1cm) (y)

I used this formula to calculate the wavelength of the red laser: d*tan(y/x) = m λ
where m = 0,1,2... and d = 1.67*10^-6 in this experiment.

The problem which I've got is that I got two different wavelengths for the same red laser
692.4nm and 765.6nm.
My question is this, should I add these two wavelengths and then divide it by two to get the "average" wavelength or should I just say in the experiment that the wavelength "765.6nm" is a random error; thus, we should not take it to the consideration?
 
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any one please, if this is a stupid question then please tell me
 
m_p_w said:
I did an experiment where a red laser went through a diffraction grating
The distance between the diffraction grating to the screen is 10cm (x)
Later I measure the distance from the central dot to the first dot (4.5cm) (y)
after this I measure the distance from the central dot to the second dot(13.1cm) (y)

I used this formula to calculate the wavelength of the red laser: d*tan(y/x) = m λ
where m = 0,1,2... and d = 1.67*10^-6 in this experiment.

The problem which I've got is that I got two different wavelengths for the same red laser
692.4nm and 765.6nm.
My question is this, should I add these two wavelengths and then divide it by two to get the "average" wavelength or should I just say in the experiment that the wavelength "765.6nm" is a random error; thus, we should not take it to the consideration?

The equation you quoted is wrong. The correct equation is d sinθ = mλ.

What you did was to replace sinθ by tanθ=y/x, so you calculated the wavelength from the formula d y/x = mλ. But sinθ can be approximated by tanθ only for small angles, that is, when y<<x. That was not valid in your experiment. Find θ=arctan(y/x), and use the formula d sinθ = mλ to get the wavelength.

ehild
 
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thank you so much
 
You are welcome.:smile:

ehild
 

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