Diffraction Grating - Resolving Power

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Homework Help Overview

The discussion revolves around a problem involving diffraction grating and resolving power, specifically analyzing light from a mercury discharge lamp with two closely spaced yellow lines at 577 nm and 579 nm. Participants are tasked with finding the angle of diffraction for the 577 nm line in second order, expected dispersion, and resolving power.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the calculation of resolving power using the formula R = λ/Δλ = Nm, expressing confusion over differing results and questioning the applicability of these results. There is also a discussion about the assumption of Δλ = 2 nm and its implications for resolving power.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the resolving power and the assumptions made regarding Δλ. Some guidance has been offered regarding the relationship between resolving power and the necessary conditions for resolution, but no consensus has been reached.

Contextual Notes

Participants are navigating assumptions about the value of Δλ and its impact on the calculations, indicating potential constraints in the problem setup. There is a focus on the implications of these assumptions for the resolving power of the grating.

Darth Frodo
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Homework Statement


4. Light from a mercury discharge lamp contains 2 yellow lines at 577 nm and 579 nm. Find the angle of diffraction for the 577 nm line in second order when passed through a grating having 2400 lines at 80 lines per mm.
What is the expected dispersion in second order in the vicinity of this line?
What is the resolving power in second order?

The Attempt at a Solution



Ok so the first part was grand. I'm having trouble with the second part,

R = \frac{λ}{Δλ} = Nm

This gives me 2 very different answers though. Which one is applicable and why? I mean, they are obviously only equal at one value for m but I don't know.
 
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Darth Frodo said:

Homework Statement


4. Light from a mercury discharge lamp contains 2 yellow lines at 577 nm and 579 nm. Find the angle of diffraction for the 577 nm line in second order when passed through a grating having 2400 lines at 80 lines per mm.
What is the expected dispersion in second order in the vicinity of this line?
What is the resolving power in second order?

The Attempt at a Solution



Ok so the first part was grand. I'm having trouble with the second part,

R = \frac{λ}{Δλ} = Nm

This gives me 2 very different answers though. Which one is applicable and why? I mean, they are obviously only equal at one value for m but I don't know.

Homework Statement



Homework Equations



The Attempt at a Solution

You're not assuming that Δλ = 2 nm, are you?



Darth Frodo said:
Shameless Bump
Yes. You waited nearly long enough for a legal bump.
 
Yes, I am assuming that Δλ = 2 nm. Why? I assume this is incorrect?
 
Darth Frodo said:
Yes, I am assuming that Δλ = 2 nm. Why? I assume this is incorrect?
2 nm is what you need to be able to resolve. -- i.e. your resolving power needs to be λ/(Δλ) .

The resolving power of the grating in second order is (m)(N) .
 

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