Engineering Diode Limiter Circuit: Input-Output Graph & Voltage Output

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The discussion revolves around a diode limiter circuit tested with a 16V sine wave at 1kHz. The user calculates the output voltage as 3.7V when the sine wave is positive and -3.3V when negative, based on the conduction states of the diodes. There is confirmation that the output graph will depict a sine wave clipped at +3.7V and -4.7V. The clarification emphasizes the expected behavior of the circuit under these conditions. The conversation concludes with agreement on the output waveform representation.
francisg3
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Hello,
I have recently had a lab on diode limiters and am a bit confused by the results. The circuit is seen in the picture below and I have obtained theoretical values for the Voltage output. The circuit is feed by a 16V sine wave with a frequency of 1kHz.

Now I know when the sine wave is positive, D1 conducts and D2 is cut-off. So the voltage output should be 3V + 0.7V = 3.7V right?

When the sine wave is negative I know that D1 is cut-off and D2 conducts. This means that the output voltage should be -4V + 0.7V = -3.3V correct?

I need to sketch the input and output so would the graph would be a sine wave clipped at +3.7V and -4.7V ?

Thanks for the help!
 

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would the graph would be a sine wave clipped at +3.7V and -4.7V ?

Yes, it would be like this.
 

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