Dirac Trace Algebra: Which Gamma Matrices Matter?

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SUMMARY

The discussion centers on the properties of Dirac gamma matrices in trace calculations, specifically addressing the rule that the trace of an odd number of gamma matrices equals zero. The participant questions whether the specific types of gamma matrices, such as $$\gamma^0$$ and $$\gamma^5$$, affect this outcome. It is concluded that while the trace remains zero due to the odd count, the treatment of $$\gamma^5$$ requires special consideration due to its unique properties in relation to other gamma matrices.

PREREQUISITES
  • Understanding of Dirac gamma matrices and their properties
  • Familiarity with trace identities in linear algebra
  • Knowledge of commutation and anticommutation relations
  • Basic concepts of quantum field theory
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  • Study the properties of Dirac gamma matrices in detail
  • Learn about the implications of trace identities in quantum field theory
  • Research the role of $$\gamma^5$$ in particle physics
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Physicists, particularly those specializing in quantum field theory, graduate students studying particle physics, and researchers working with Dirac matrices and trace calculations.

Maurice7510
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Homework Statement


This isn't a homework problem; it's just something I'm working on and I'm a little confused as to how to go about dealing with what I have. I have several traces of Dirac's gamma matrices, and I know that the trace of an odd number of gamma matrices is zero. So my first question is: does it matter *which* gamma matrices? For example, one of my traces has
$$ \gamma_{\nu}\gamma^5\gamma^{\rho}\gamma^{\alpha}\gamma^{\sigma}\gamma^0\gamma^5\gamma^0\gamma^{\lambda}\gamma_{\mu}\gamma^{\beta} $$ Since each $$\gamma^5$$ is a product of 4 gamma matrices, altogether this would be a product of 17, which is odd. But some are $$\gamma^{\mu}$$, some $$\gamma^0$$ and some $$\gamma^5$$ and I'm just not sure what the rules are for this type of thing.

Homework Equations


$$Tr (ABC) = Tr (CAB) = Tr (BCA)$$
$$Tr (A +B) = Tr(A)+Tr(B)$$
$$Tr(aA) = aTr(A)$$

The Attempt at a Solution


I would think that this would, in fact, still be zero because there's an odd number of them. Otherwise I would probably use commutation/anticommutation relations to bring the $$gamma^0$$ and $$\gamma^5$$ together (respectively) to get unity, then just deal with the rest.
 
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Maurice7510 said:
zero because there's an odd number of them.
And there is your answer.
 
So does that mean that all the standard trace identies for gamma matrices (e.g. in Griffiths or Peskin Schroeder) hold for *any* gamma matrices, regardless of their index?
 
Maurice7510 said:
*any* gamma matrices, regardless of their index?
As long as that index is 0, 1, 2, or 3. You will need to treat ##\gamma^5## differently.
 
Isn't the last one just a product of the first 4?
 
Maurice7510 said:
Isn't the last one just a product of the first 4?
Yes (up to a factor), so you need to treat it differently.
 

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