Direction of Induced EMF (Faradays Law) Confusion

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SUMMARY

The forum discussion centers on the confusion surrounding the direction of induced electromotive force (EMF) as described by Faraday's Law. The participant analyzes the relationship between the current i(t) and the induced voltage e_{ind}, noting that if i(t) is increasing, e_{ind} is negative relative to voltage v, and vice versa if i(t) is decreasing. The participant emphasizes the importance of understanding the sign difference in their expressions for voltage and induced EMF, which directly impacts subsequent calculations. The discussion highlights the necessity of clarifying whether the current is increasing or decreasing to accurately determine the direction of induced voltage.

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Homework Statement



See figure attached.

Homework Equations





The Attempt at a Solution



If we attempt to solve part a) in this question we encounter several confusions.

If we assume i(t) to be a positive current, the magnetic flux will flow through the core in a counter clockwise direction.

How are we supposed to deduce the direction of the induced voltage,

[tex]e_{ind}[/tex]

?

If you tell me whether or not i(t) is increasing or decreasing or remaning constant I can then tell you how eind relates to v.

Are we just supposed to assume it is either increasing or decreasing? If so, the relation to v to eind will have a sign difference in each case.

Assume i(t) is increasing,

[tex]e_{ind} = -v = -\frac{d\psi}{dt}[/tex]

Assume i(t) is decreasing,

[tex]e_{ind} = v = -\frac{d\psi}{dt}[/tex]

As you can, depending on which case I assume, my expression of v will change by a negative sign.

This will affect the answer in part b).

How do we know which one to choose?
 

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Looking at the picture, I take the up arrow to indicate positive current, an increasing current causes the polarity as indicated in the coil N2? So for part b increasing current leads to positive voltage? Any others?
 
Spinnor said:
an increasing current causes the polarity as indicated in the coil N2

Thus,

[tex]e_{ind} = v = -\frac{d\psi}{dt} = -\frac{250\mu_{0}N_{1}N_{2}d^{2}}{a}\frac{di(t)}{dt}[/tex]

Why does my expression for v turn out to be negative while theirs is positive?

I was told that the expression for eind is always,

[tex]e_{ind} = -\frac{d\psi}{dt}[/tex]

I agree that the positive induced current, if i(t) is increasing, will flow from the positive terminal of v to the negative terminal of v.
 
Last edited:

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