Direction of particle between two plates

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Fatima Hasan
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Homework Statement


Physics problem Q4 with a diagram of two horizontal parallel plates, the upper negatively charged and the lower positively charged, with a small charged particle m+q between them and a z-y-x coordinate axis. Answer options (A) to (E) are listed below.


Homework Equations


Three equations typeset in plain text: Fg = mg, E = σ/ε0, and Fel = EQ, the last cut off at the right edge of the image.


The Attempt at a Solution


Three lines of worked calculation: Fg = mg = 0.36 * 10^-3 * 10 = 3.6 * 10^-3 N; E = sigma/epsilon0 = 3 * 10^-6 / (8.85 * 10^-12) = 338.98 * 10^3 N/C; Fel = EQ = 338.989 * 10^3 * 11.8 * 10^-9 = 4 * 10^-3 N.

Since Fel > mg , the particle will move up with acceleration
 
Attachments
  • Physics problem Q4 with a diagram of two horizontal parallel plates, the upper negatively charged and the lower positively charged, with a small charged particle m+q between them and a z-y-x coordinate axis. Answer options (A) to (E) are listed below.
    image.jpg
    35.4 KB · Views: 630
  • Three equations typeset in plain text: Fg = mg, E = σ/ε0, and Fel = EQ, the last cut off at the right edge of the image.
    screenshot_15.png
    2.6 KB · Views: 672
  • Three lines of worked calculation: Fg = mg = 0.36 * 10^-3 * 10 = 3.6 * 10^-3 N; E = sigma/epsilon0 = 3 * 10^-6 / (8.85 * 10^-12) = 338.98 * 10^3 N/C; Fel = EQ = 338.989 * 10^3 * 11.8 * 10^-9 = 4 * 10^-3 N.
    screenshot_13.png
    7.7 KB · Views: 649
Last edited:

Discussion

Nguyen Son said:
What is your question?
want to know where is my mistake as I didn't get the same answer as the model answer
 
Fatima Hasan said:
want to know where is my mistake as I didn't get the same answer as the model answer
Your calculations and conclusion look okay to me.
 
  • Like
Likes   Reactions: Fatima Hasan
gneill said:
Your calculations and conclusion look okay to me.
My answer turns out to be correct;Thanks !
 

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