Discover the Force Needed for a Man to Rise on a Bosun Chair | Mass=95Kg

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To rise in a bosun chair with a combined mass of 95 kg, the man must exert a force of approximately 450 N on the rope to achieve equilibrium. This force balances the weight of the man and chair, which is about 950 N. If he pulls with a force greater than 450 N, he will accelerate upward. The discussion also touches on the need for accurate free body diagrams to analyze the forces involved. Overall, understanding the forces acting on the system is crucial for determining the required pulling force.
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A small man is sitting in a bosun chair that dangles from a massless rope, which runs over a massless frictionless pulley and back down to the mans hand. The combined mass of the man and the chair is 95kg. with what force magnitude must the man pull on the rope if he is to rise?

Mass = 95Kg
a = ?
v = ?
F = ?

I didnt get very far with this one, I drew one F.B.D for the man and got the following:
Nothing in the X direction
y--------T+v = -mg

Heres a link to a drawing
http://img438.imageshack.us/img438/8349/pulley27xt.png

Should i draw another F.B.D for the mans hands on the rope?
 
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if so would T act up onlong with mg and v act downwards?
 
Hi, the weigh of the man + weigh of the chair is around 950 N.
When the man pulls hiomself with his hand with a force F, the chair exerts also a force F on him.
Just to have equilibrium 2F = 950 N so F = 450 N
With a little push up (say with his feet on the ground) the chair and him will move up at a constant speed if he maintains the constant force 450 N on the rope
Any force greather than 450 N will cause an acceleration of the man and the chair up in the air.
I hope it helps you
 
so there's no math involved?
kinda makes sense since there are 3 unknows..

2f = 931N
f = 465.5N

Also there is more to the question..si are my free body diagrams correct?
 
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