Discover the Power of Maclaurin Series: A Comprehensive Guide

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Homework Help Overview

The discussion revolves around the Maclaurin series and its application, particularly focusing on the estimation of the remainder term in a Taylor series and the calculation of maximum error associated with it.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the radius of convergence and the need for a formula for the remainder term. Questions arise regarding the maximum error and the meaning of the variable M in the context of the remainder formula.

Discussion Status

Some participants have provided links to resources for further understanding, while others are exploring different formulas and their implications. There is a mix of attempts to clarify concepts and share information, but no explicit consensus has been reached on the maximum error calculation.

Contextual Notes

Participants mention constraints related to classroom instruction and the need for specific formulas as directed by their teacher. There is also a note on the importance of maintaining the thread for future reference by others facing similar challenges.

irunshow
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solved thanks
 
Last edited:
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Yes, the first part is correct. The limit of the ratios is 0 so the radius of convergence is infinite. For the second part you need a form for the remainder term in a Taylor series. Weren't you given one? If not look it up and try to estimate it.
 
Thanks Dick,

Yea my teacher didnt explain it in class cause there was no time left.
Is there a general formula to calculate the max error?

Thanks
 
Hey dick,

thanks but i think my teachers wants to do it with this formula:

abs(Rn(x)) less than or equal to (M)/(n+1)! abs(x-a)^(n+1)

I don't know what the M equals to tho
 
irunshow said:
Hey dick,

thanks but i think my teachers wants to do it with this formula:

abs(Rn(x)) less than or equal to (M)/(n+1)! abs(x-a)^(n+1)

I don't know what the M equals to tho

M is a bound for the k+1 derivative of f(x) over the interval. Look at the link I sent you. You'll see f^(k+1) instead of M.
 
Hi i got the answer to be 0.0317.
Is that correct?

Thanks =)
 
irunshow said:
solved thanks

Don't delete the problem after you've solved it! Other people with similar problems are supposed to be able to search for previous threads that can help them. Deleting parts of it defeats that.
 
edit: kk i won't next time xD
 

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