yilbaris
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We all know the lift force in case 1, what about case 2 ?
The discussion revolves around understanding the lift force in a specific scenario referred to as "case 2," contrasting it with a previously established "case 1." Participants explore the nature of forces acting on submerged objects, particularly focusing on buoyancy and lift, and the complexities involved in calculating these forces.
Participants express differing views on the definitions and implications of lift force versus buoyancy. There is no consensus on the complexities of calculating resultant forces or the distribution of forces acting on submerged surfaces.
Limitations in the discussion include assumptions about the conditions under which forces are calculated and the potential confusion between static and dynamic forces. Some mathematical steps regarding force distribution remain unresolved.
If by "lift force", you actually mean "buoyancy", this can be calculated for case 2, although it is slightly more complicated than case 1.yilbaris said:We all know the lift force in case 1, what about case 2 ?View attachment 89160
A force can never equal a pressure, the dimensions are different. An area element is subjected to a normal force equal to the pressure multiplied by the areaMrAnchovy said:Every point on the submerged surface of the object feels a normal force equal to the pressure at that depth ## \rho g h ##
I wanted to steer clear of elemental areas for the sake of clarity but I take your point; I have amended 'equal' to 'proportional'.Orodruin said:A force can never equal a pressure, the dimensions are different. An area element is subjected to a normal force equal to the pressure multiplied by the area