Discovering Lift Force in Case 2

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We all know the lift force in case 1, what about case 2 ?
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yilbaris said:
We all know the lift force in case 1, what about case 2 ?View attachment 89160
If by "lift force", you actually mean "buoyancy", this can be calculated for case 2, although it is slightly more complicated than case 1.

Remember Archimedes' Principle:

https://en.wikipedia.org/wiki/Archimedes'_principle

Note: in technical use, "lift force" is usually reserved for a force which is created by a dynamic situation, like the lift generated by an airplane's wings when flying.
OTOH, "buoyancy" usually refers to a force created by a static situation, like the displacement of fluid by a floating object.
 
Thank you for answers,

? To calculate the resultant force is possible, but i wonder distribution of force. ?
 
Every point on the submerged surface of the object feels a normal force proportional to the pressure at that depth ## \rho g h ##
 
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MrAnchovy said:
Every point on the submerged surface of the object feels a normal force equal to the pressure at that depth ## \rho g h ##
A force can never equal a pressure, the dimensions are different. An area element is subjected to a normal force equal to the pressure multiplied by the area
 
Thank you all.

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Orodruin said:
A force can never equal a pressure, the dimensions are different. An area element is subjected to a normal force equal to the pressure multiplied by the area
I wanted to steer clear of elemental areas for the sake of clarity but I take your point; I have amended 'equal' to 'proportional'.