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That's all correct. If you use my convention of the signs, i.e.,rude man said:This equation indicates B leading E by 45 deg. which is incorrect unless you're making an assumption that I can't fathom. B should lag by 45 deg. I, vanhees & the problem's statement all agree on this. So your error must have taken place ahead of this relation unless, again, somewhere there's an inconsistency regarding convention.
\vec{B} \propto \exp(-\mathrm{i} \omega t).
Your case is for a good conductor, i.e., \sigma \mu \omega \gg \epsilon \mu \omega^2 or
\frac{\sigma}{\epsilon} \gg 1.
Then you have
k \simeq \sqrt{\frac{\sigma \mu}{\omega}} \exp(+\mathrm{i} \pi/4).
That means
B_0 \exp(-\mathrm{i} \omega t)=\sqrt{\frac{\sigma \mu}{\omega}} E_0 \exp[-\mathrm{i}(\omega t-\pi/4)].
This means the phase of the B field is behind that of the E field by an amount of \pi/4 (in the limit of good conductivity).