i just studied S.H.M and i am wondering is the displacement equals the amplitude or zero after the periodic time?

because when i thought it equals zero at first because the periodic time is time required for the object to make acomplete oscillation and return to it's starting point right?

but when i put the law T= [tex]2\pi\ \sqrt{m/k}[/tex]

T= [tex]2\pi\ *\sqrt{m/f/x}[/tex]

T= [tex]2\pi\ *\sqrt{m/mg/x}[/tex]

T=[tex]2\pi\ *\sqrt{x/g[/tex] (and unless the periodic time of every S.H.M is 0 this cant be right )

and no this isn't home but i asked the tried to ask the teacher and he didnt have time to listen.

And this is like my first lesson in S.H.M so i dont understand it that much.

maybe i didnt understand the periodic time right or something like that

also since y = A Sin (wt)

y = Asin ([tex]2\pi/T\[/tex]*T

y = Asin([tex]2\pi[/tex]=0

because when i thought it equals zero at first because the periodic time is time required for the object to make acomplete oscillation and return to it's starting point right?

but when i put the law T= [tex]2\pi\ \sqrt{m/k}[/tex]

T= [tex]2\pi\ *\sqrt{m/f/x}[/tex]

T= [tex]2\pi\ *\sqrt{m/mg/x}[/tex]

T=[tex]2\pi\ *\sqrt{x/g[/tex] (and unless the periodic time of every S.H.M is 0 this cant be right )

and no this isn't home but i asked the tried to ask the teacher and he didnt have time to listen.

And this is like my first lesson in S.H.M so i dont understand it that much.

maybe i didnt understand the periodic time right or something like that

also since y = A Sin (wt)

y = Asin ([tex]2\pi/T\[/tex]*T

y = Asin([tex]2\pi[/tex]=0

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