Displacment in simple harmonic motion after periodic time

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Homework Help Overview

The discussion revolves around understanding displacement in simple harmonic motion (S.H.M) and its relationship to periodic time. The original poster expresses confusion about whether displacement equals amplitude or zero after one complete oscillation, as well as the implications of various equations related to S.H.M.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between displacement and periodic time, questioning the meaning of displacement at different points in the oscillation. There are attempts to clarify the equations governing S.H.M, including the forms of displacement equations based on starting conditions. Some participants express uncertainty about the implications of setting displacement to zero in calculations.

Discussion Status

The discussion is ongoing, with participants seeking clarification on concepts and equations related to S.H.M. There is a mix of attempts to derive relationships and questions about the correctness of the information shared. Some guidance has been offered regarding the forms of equations based on initial conditions, but no consensus has been reached.

Contextual Notes

Participants note their limited understanding of S.H.M and express a desire to confirm their grasp of the relevant laws and concepts. There is an acknowledgment of confusion regarding the calculations leading to zero displacement and the implications of various parameters in the equations.

madah12
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i just studied S.H.M and i am wondering is the displacement equals the amplitude or zero after the periodic time?
because when i thought it equals zero at first because the periodic time is time required for the object to make acomplete oscillation and return to it's starting point right?

but when i put the law T= [tex]2\pi\ \sqrt{m/k}[/tex]
T= [tex]2\pi\ *\sqrt{m/f/x}[/tex]

T= [tex]2\pi\ *\sqrt{m/mg/x}[/tex]

T=[tex]2\pi\ *\sqrt{x/g[/tex] (and unless the periodic time of every S.H.M is 0 this can't be right )and no this isn't home but i asked the tried to ask the teacher and he didnt have time to listen.
And this is like my first lesson in S.H.M so i don't understand it that much.
maybe i didnt understand the periodic time right or something like that

also since y = A Sin (wt)
y = Asin ([tex]2\pi/T\[/tex]*T
y = Asin([tex]2\pi[/tex]=0
 
Last edited:
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Well if you start at max displacement then your equation for SHM will be of the form
y=Acos(wt)

if you start at zero minimum displacement, it will be of the form y=Asin(wt)
 
But i still don't understand
if we try to calculate T
then we are trying to calculate the time the displacement reach 0 right?
so if the displacement is 0
then
T =[tex]\sqrt{Y/g}[/tex] right so if Y is zero wouldn't the T always be 0?(for the displacement i can use symbol X or Y right?)
 
madah12 said:
T=[tex]2\pi\ *\sqrt{x/g[/tex] (and unless the periodic time of every S.H.M is 0 this can't be right )

What is x??
 
displacement.
isn't it from hook's law
that f=x*k
so k= f/x
so i putted that value in the law for the periodic time
and i got T = root of x / root of g

Edit: i am really new to simple harmonic motion and i am not very good at physics therefore i am trying to understand the laws better but i still don't understand the concept of S.H.M
what i know of it is that its a motion of an object where the acceleration increase with the displacement but in the opposite direction and that oscillation is when the object goes through the max displacement to the right then to the left then return to where it started and the time for that is called the periodic time.

and that the object move with an angular speed (omega) which is the magnitude of the angular velocity which is measured by radian and it decrease when the acceleration increases.
and that the acceleration reach's it maximum when the object reaches the amplitude while the velocity become 0 and velocity reaches its maximum when the object return to it's starting place.(this is all i know about simple harmonic motion but i am trying to calculate T by displacement but always get zero as an answer)

these are the only laws i know
w=theta/t
w =[tex]2\pi\ /T[/tex]
y=Asin(wt)
T=[tex]2\pi\ *\sqrt{m/k}[/tex]
a=-w^2*Asin(wt)=w^2*y
amax=+or-w^2*A
V=w*[tex]\sqrt{A^2-y^2}[/tex]
Vmax=w*A
(fmax =k*A. i don't know if that is alaw since it isn't written in my book but it make since the returning force increase with the displacement it should be at max at the amplitude right?)
But i am trying to put alaw to combine the periodic time and the displacement but i can't do that.without always getting zeros

So i want to know what i am doing wrong anyone can help with that?
 
Last edited:
I don't really need some one to form the law for me i just want to make sure that the laws and info i have are correct and maybe little advice on where to begin
 

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