If you are in a helicopter and the helicopter lifts off at a constant acceleration of 5.0m/s^2 for 11.0 seconds, what is the total distance travelled from the ground?
y = yo + voyt + 1/2*ax*t^2
The Attempt at a Solution
y = 0 + 0 + 1/2(5m/s^2)(11^2)
y = 3*10^2m
But, apparently the actual answer is 4.6*10^2m.