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Distance, Acceleration and Time Question

  1. Oct 11, 2012 #1
    1. The problem statement, all variables and given/known data

    If you are in a helicopter and the helicopter lifts off at a constant acceleration of 5.0m/s^2 for 11.0 seconds, what is the total distance travelled from the ground?

    2. Relevant equations

    y = yo + voyt + 1/2*ax*t^2

    3. The attempt at a solution

    y = 0 + 0 + 1/2(5m/s^2)(11^2)

    y = 3*10^2m

    But, apparently the actual answer is 4.6*10^2m.
     
  2. jcsd
  3. Oct 12, 2012 #2

    SammyS

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    Check your arithmetic.


    Added in Edit:
    I'll check mine instead !

    DOH !
     
    Last edited: Oct 12, 2012
  4. Oct 12, 2012 #3

    Simon Bridge

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    Guess I have to check mine too :(
     
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