Distance between m=0/m=1 bright fringes

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SUMMARY

The distance between the m=0 and m=1 bright fringes for a double-slit experiment with slits separated by 2.00x10^-5 meters and illuminated by light of wavelength 500 nm is calculated using the formula d = m * λ * L / y. The correct calculation yields a distance of 20 cm, not 10 cm as initially stated. The confusion arose from misinterpreting the fringe order and the application of the formula.

PREREQUISITES
  • Understanding of double-slit interference principles
  • Familiarity with the formula d = m * λ * L / y
  • Knowledge of wavelength measurement in nanometers
  • Basic trigonometry for small angle approximations
NEXT STEPS
  • Review the derivation of the double-slit interference formula
  • Learn about fringe spacing in interference patterns
  • Explore the impact of slit separation on interference patterns
  • Study the differences between bright and dark fringe calculations
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Students studying wave optics, physics educators, and anyone interested in understanding interference patterns in light experiments.

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Homework Statement


Two slits separated by 2.00x10^-5 are illuminated by light of wavelength 500nm. If the scree is 8.0m from the slits what is the distance between m = 0 and m=1 bright fringes?
answer is 10 cm

Homework Equations


d=m*lambda*L/y (for the short cute..for small angles)




The Attempt at a Solution


at m=0 d=0

at m=1
d=1*(500*10^-9)(8.0 m)/(2.0*10^-5) = 0.2m

so I am getting double...but I can't find a reason t multiply it by 1/2 ...

hmm
please help!

also, do i alway use m for bright fringe and (m+1/2) for dark...?
 
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I figured out there was a mistake on the answer sheet and the answer is 20 cm


haha thanks anyways
 

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