Distance between two point charges as a function of time.

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SUMMARY

The discussion centers on solving the motion of two point charges under the influence of Coulomb's law, specifically how to express the distance between them as a function of time. The user derives the equations of motion using Newton's second law, leading to a second-order differential equation. The key equation derived is 2U/d² = d'', where U is defined as kq1q2/m. The user seeks to understand the behavior of the distance delta x as time progresses, particularly whether it approaches zero and at what rate.

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  • Understanding of Coulomb's law and electrostatics
  • Familiarity with Newton's second law of motion
  • Basic knowledge of differential equations, particularly second-order equations
  • Concept of separable differential equations
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  • Study the solution techniques for second-order differential equations
  • Learn about separable differential equations and their applications
  • Explore the implications of Coulomb's law in dynamic systems
  • Investigate numerical methods for solving differential equations in physics
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Students of physics and mathematics, particularly those studying electromagnetism and differential equations, as well as researchers interested in dynamic systems involving electrostatic forces.

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Edit: Apparently Coulomb's law only holds for electrostatics... in that case I understand that this problem is physically impossible. I'd still like to solve it if we assumed that coulomb's law did hold for moving charges

If there are two point charges that are initially separated by (x10-x20), which exert a force kq1q2/(x1-x2)^2 on each other, how can I find delta x (x1 - x2) as a function of time?

When I use f = mx'', I get kq1q2/(x1-x2)^2 = mx''

or if i introduce a new variable U = kq1q2/m, it's U/(x1-x2)^2 + x1'' = 0 for the first and U/(x1-x2)^2 - x2'' = 0 for the second force.

I don't know where to go from here. I want to solve for (x1-x2) given the initial conditions. I'm not well versed in differential equations, because I'm only now starting my first semester of differential equations, but I want to say that this is a linear second order partial differential equation? I feel like it might be not difficult to solve because of the symmetry.

Can it be solved? Because the question has been haunting me for months, I'm just so darn curious. Obviously if they are attractive, delta x will approach 0 at an incredibly fast acceleration. At what time point does delta x equal 0? Or will it just approach 0 forever?

I'm new here and this is my first post, but I thought that rather than go bother my differential equations professor I would try posting it here first!
 
Last edited:
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You already have these (I haven't double-checked anything):

U/(x1-x2)^2 + x1'' = 0
U/(x1-x2)^2 - x2'' = 0

Just add the two equations, and defind d(t) = x2(t)-x1(t).

This gives you an quation

2U/d^2 = d''

which is a separable differential equation.

Torquil
 

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