Distance Formula: Find JK Distance to Nearest Tenth

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The discussion centers on finding the distance between two points, J(2,-1) and K(2,5), using the distance formula. The user initially calculates the distance but expresses confusion about their method. It is confirmed that the calculation is correct, as the x-coordinates are the same, simplifying the problem to finding the difference between the y-coordinates. The user appreciates the clarification and acknowledges that recognizing the simplification would have saved time. Overall, the conversation highlights the importance of understanding the distance formula and its application in specific cases.
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Yah, easy I know, but I got a little confused. Okay, here's the problem:
Find the distance between the points to the nearest tenth. J(2,-1) K(2,5) Here's what I did. d=√(2-2)^2+(5-(-1)^2 (the ^2 means squared) √(2-2)^2=0 so I'm left with √(5-(-1)^2= √(6)^2= √36=6 Ok, so how did I do? I wasn't sure if what I did was right, I think so, but I just needed to make sure. Thanks.
 
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Your solution is correct.
 
In fact, in that case, since the x coordinates of (2,-1) and (2,5) are the same so the distance is just the distance between -1 and 5 on a number line: 5-(-1)= 6.
 
Oh, yah I never thought about that. Heh, that would have saved some time, I'll remember that! Thanks to both of you.
 

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