Distance Traveled by Point on Wheel: Rotational Motion

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Homework Help Overview

The problem involves a wheel with a diameter of 40 cm that accelerates uniformly from 240 rpm to 360 rpm over a period of 6.5 seconds. The original poster seeks to determine the distance traveled by a point on the edge of the wheel during this time.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of angular velocity and rotational kinematics equations. There is an exploration of converting between revolutions and radians, as well as the relevance of the wheel's diameter in calculating linear distance.

Discussion Status

The discussion has progressed with participants offering guidance on the appropriate equations to use for angular displacement and the need for unit conversions. There is an ongoing clarification regarding whether the problem requires linear distance or angular displacement.

Contextual Notes

Participants are considering the implications of the wheel's diameter in relation to the type of distance being calculated, and there is a focus on ensuring the problem's requirements are fully understood before proceeding.

sw3etazngyrl
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A 40cm diameter wheel accelerates uniformly from 240rpm to 360rpm in 6.5s. How far will a point on the edge of the wheel have traveled in this time?


I think we have to use w=2pi*f?


I used that equation and plugged in w=2pi*(120rpm/0.108min)=1107.69 revolutions. I don't know where to go from there.
 
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I'm not sure what you mean by "w," if that's your omega, you'll need to use a different approach. You're given the initial angular speed, and the final angular speed in revolutions per minute. The object has a constant angular acceleration, so you can use the equations for rotational kinematics. You'll probably want to use \theta = .5(\omega_0 + \omega) t. Does that help?
 
ohh, yea, i think i get it. so the eq. would be:

theta = .5 (240 + 360)(0.108)?
 
You've got it. Just remember to convert units if you must.
 
Thanks!
 
so for distance, how should i find that? my answer is in radians.
 
Ok, so your theta is going to be in revolutions. If you want radians, you convert using the fact that 1 revolution equals 2\pi radians. Does that help?
 
yes, it does. so the 40cm is irrelevant?
 
sw3etazngyrl said:
yes, it does. so the 40cm is irrelevant?

Well, if we were asked the linear distance traveled by the point, then it would be necessary. But if we're simply considering its angular displacement over some period of time, it's not necessary. Make sure the problem doesn't ask for linear distance.
 
  • #10
it's asking for the distance the edge of wheel will be at or have traveled
 
  • #11
As in a wheel rolling across the ground?
 
  • #12
i think so
 
  • #13
i got it now, THANKS!
 
  • #14
You're welcome. I'd just ask that you be 100% sure it's not asking for the linear distance. If it is, you'll have to use the "rolling constraints" v_{linear} = \omega r, a_{linear} = \alpha r. If it's asking for the answer in radians or revolutions, then you're good to go, I wouldn't want you getting the wrong answer :)
 

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