Єr = 3.0, atomic density = 1028 atoms/m3. The mag. of the E-field is 10,000 [V/m]. Two electrons in outer orbital shell will distort with an applied E-field. If both both electrons follow some orbital path as a pair, find spacing between center of nucleus and average location of electrons.
Єr = 1 + Χe
Є = Єo*Єr
P = Єo*Χe*E
The Attempt at a Solution
If I solve for the magnitude of polarization, I come up with mag(P) = Єo*Χe*mag(E). If so, I receive mag(P) = 1.771e-7 [V/m]. If need be, the magnitude of the electric flux density is: mag(D) = Є*mag(E) = 2.66e-7 [C/m2]. What is really throwing me off is the atomic density! I have no idea how to incorporate this it does not seem applicable with any of the formulas in my text. I am kind of confused by this problem, in general. I do not know how to get past my attempt above at working some of the variables.
I appreciate any help you may be able to give me, and I thank you sincerely in advance!