Is There a Hole at X=0 for F(X)= X/Sin(X)?

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The function F(X) = X/Sin(X) has a hole at X=0 due to the indeterminate form 0/0, making it undefined at that point. However, the limit as X approaches 0 is defined, indicating that the function approaches a value despite being undefined at zero. The discussion clarifies that there is no oblique asymptote for this function, as the conditions for such an asymptote do not apply due to the transcendental nature of the denominator. Participants express confusion over terminology, particularly regarding the distinction between asymptotes and tangents. Ultimately, the consensus is that while there is a hole at X=0, there is no oblique asymptote present.
CanadianEh
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Hi there,
Quick question. For F(X)= X/Sin(X), is there a hole at X=0?

Thanks.
 
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What do you get when plugging 0 into F(X) ?
 
CanadianEh said:
Hi there,
Quick question. For F(X)= X/Sin(X), is there a hole at X=0?

Thanks.

Hi CanadianEh! :smile:

At x = 0, obviously, it's 0/0, which is undefined (it's known as an "indeterminate form"), so yes in that sense there's a hole …

of course, F(x) does tend to a limit at as x -> 0 :wink:
 
0/Sin 0 = undefined.

So basically, there's my answer. There is a hole at x=0. There is also an oblique asymptote of f(x)=x, correct?
 
tiny-tim said:
Hi CanadianEh! :smile:

At x = 0, obviously, it's 0/0, which is undefined (it's known as an "indeterminate form"), so yes in that sense there's a hole …

of course, F(x) does tend to a limit at as x -> 0 :wink:


Thanks so much! Can you help me explain why there is an oblique asymptote?
 
CanadianEh said:
Thanks so much! Can you help me explain why there is an oblique asymptote?

uhh? :blushing:

wot's an oblique asymptote? :confused:
 
When a linear asymptote is not parallel to the x- or y-axis, it is called either an oblique asymptote or equivalently a slant asymptote.

In the graph of X/Sin(X), there appears to be an asymptote at y=x
 
The function continues to have a defined value as you get arbitrarily close to zero, thus the limit as x->0 is defined. The function itself is undefined only exactly at zero.

- Warren
 
Try graphing x/sin(x) and you'll only see vertical asymptotes when the denominator, or sin(x), is 0.
As far as I know, a rational function P(x)/Q(x) where P and Q are polynomials has an oblique asymptote only when the degree of the numerator is one larger than that of the denominator. In x/sin(x) you have a transcendental function in the denominator.
 
  • #10
Ok, so NO oblique asymptote, correct?
 
  • #11
CanadianEh said:
When a linear asymptote is not parallel to the x- or y-axis, it is called either an oblique asymptote or equivalently a slant asymptote.

In the graph of X/Sin(X), there appears to be an asymptote at y=x

Still totally confused as to why this is called an asymptote instead of a tangent. :confused:

Anyway I can't see how it's slanting ……

what is limx -> 0 x/sinx ? :smile:
 
  • #12
CanadianEh said:
Ok, so NO oblique asymptote, correct?
That's right.
tiny-tim said:
uhh? :blushing:

wot's an oblique asymptote? :confused:

A slant asymptote
http://home.att.net/~srschmitt/precalc/precalc-fig12-03.gif
 
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  • #13
Bohrok said:
A slant asymptote

So that's only at infinity? :blushing:
 
  • #14
and also negative infinity if the domain goes there too.
 
  • #15
tiny-tim, the word "asymptote" was wrong here. He intended "tangent" as you suggested. Because there is a "hole" at x= 0, there is no tangent there.
 

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