Do Angular Momentum Components Commute with Nabla Squared and r Squared?

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SUMMARY

The discussion focuses on the commutation relations of the angular momentum components L_x, L_y, and L_z with the operators nabla squared (∇²) and r squared (r² = x² + y² + z²). It establishes that the commutator [L_x, ∇²] can be expressed as L_x ∇² - ∇² L_x, leading to specific expressions involving derivatives. The participants suggest rewriting ∇² and applying the commutator to a differentiable function f(x,y,z) to simplify the equations further.

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Homework Statement


Show the three components of angular momentum: L_x, L_y and L_z commute with nabla^2 and r^2 = x^2 + y^2 = z^2

Homework Equations


[A, B] = AB - BA
For example:
[itex] [L_x, \nabla^2] = L_x \nabla^2 - \nabla^2 L_x[/itex]

The Attempt at a Solution


[itex] L_x \nabla^2 = -i\hbar(y\frac{\partial}{\partial z} \nabla^2 - z \frac{\partial}{\partial y}\nabla^2)[/itex]

[itex] \nabla^2 L_x = -i\hbar\nabla^2(y\frac{\partial}{\partial z} - z \frac{\partial}{\partial y})[/itex]

How can I simplify these?
 
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If you have no better ideas, then why not rewrite [itex]\nabla^2[/itex], just like you did with [itex]L_x[/itex]?
 


after rewriting [itex]\nabla^2[/itex] as Hurkyl suggested, you should apply the commutator (it is also an operator) to a differentiable function [itex]f(x,y,z)[/itex] and see whether the differentiation rules (e.g.differentiation of a product) make the equation look simplier.
 

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