- #1
richbass
- 12
- 0
I'm having trouble with a particular law, the one that says "heavier objects DO NOT fall faster" Now all experiments I've read were conducted or theorized in an atmoshere. This variable must be removed. To see the correct interaction of 2 different bodies of mass one must experiment in a vacuum, or in space. After all, the total mass of the Earth is "all of it" from the core to the outer atmosphere. So to be accurate, you must be beyond the physical mass of the object. Wether it be solid, liquid or gas. Friction must not be an issue, and the gravity sphere of these objects is obviously greater than their physical dimensions.And another thing "To any object of mass, gravity and acceleration are exactly the same."
If you understand me I can go on. Here is my experiment:
We will fashion 2 objects, here on Earth. Both will be 1 foot in diameter. Object A weighs 100kg and object B weighs 1kg."here on Earth". Now let's take them both away from Earth and close to something very massive. A neutron star perhaps. Now we will manuver both objects to a distance from the star that gravity begins to be felt. We go to a distance that each object feels the same attraction they felt back on earth. To keep these objects from "falling" we must use 100 times the force on object A as object B.
Now this 100 to 1 ratio can be directly compared to acceleration rate or G forces. Now release them both. I must conclude that object A will be traveling faster than object B at various distances when compared to each other, or another way to look at it would be it takes less time for object A to travel 100 km than object B.
Do you agree with this? If not, can you tell me logically why this is not the case?
This next paragraph was taken from: Answered by: Dr. Michael Ewart, Researcher at the University of Southern California
"If no air resistance is present, the rate of descent depends only on how far the object has fallen, no matter how heavy the object is. This means that two objects will reach the ground at the same time if they are dropped simultaneously from the same height. This statement follows from the law of conservation of energy and has been demonstrated experimentally by dropping a feather and a lead ball in an airless tube."
What I say is: In this experiment there wasn't enough distance for the actual behavior to be observed.
If you understand me I can go on. Here is my experiment:
We will fashion 2 objects, here on Earth. Both will be 1 foot in diameter. Object A weighs 100kg and object B weighs 1kg."here on Earth". Now let's take them both away from Earth and close to something very massive. A neutron star perhaps. Now we will manuver both objects to a distance from the star that gravity begins to be felt. We go to a distance that each object feels the same attraction they felt back on earth. To keep these objects from "falling" we must use 100 times the force on object A as object B.
Now this 100 to 1 ratio can be directly compared to acceleration rate or G forces. Now release them both. I must conclude that object A will be traveling faster than object B at various distances when compared to each other, or another way to look at it would be it takes less time for object A to travel 100 km than object B.
Do you agree with this? If not, can you tell me logically why this is not the case?
This next paragraph was taken from: Answered by: Dr. Michael Ewart, Researcher at the University of Southern California
"If no air resistance is present, the rate of descent depends only on how far the object has fallen, no matter how heavy the object is. This means that two objects will reach the ground at the same time if they are dropped simultaneously from the same height. This statement follows from the law of conservation of energy and has been demonstrated experimentally by dropping a feather and a lead ball in an airless tube."
What I say is: In this experiment there wasn't enough distance for the actual behavior to be observed.