Do I need to integrate twice for calculating velocity in Kerbal Space Program?

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To calculate the maximum velocity of a ship in Kerbal Space Program, integration is necessary. The user derived an equation for acceleration based on the relationship between force, mass, and fuel consumption. The discussion clarifies that to obtain velocity, one must integrate the acceleration function, which may require integrating twice if starting from jerk. A linked paper provides additional insights on the integration process. The user is encouraged to explore the paper for further clarification on their specific questions.
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So i was playing Kerbal Space Program and decided i wanted to calculate the maximum velocity of my ship. First, I formed this equation. A(t) = M - dm/dt (t) Where A is the amount of fuel at a given time, M is the total mass of the fuel, Dm/dt is the rate of change of the mass of the fuel, and t is time. As far as experiments in game show this equation works. The problem occurs when i want to calculate the maximum velocity. First i differentiated F = MA and solved for da/dt which gave me -F(dm/dt)/m^2 = da/dt. This gives me the jerk and i believe by multiplying it by t I can get the acceleration at a given time. (-F(dm/dt)/m^2 )(t) = a(t) .
From here I'm stuck. I can conceptualize how to obtain the velocity from this point. I started thinking of summation and that lead me take the integral. So my question is could I get the velocity at a given time by integrating this equation (-F(dm/dt)/m^2 )(t) = a(t)? Not sure if i provided enough information but thanks to anyone who can help.
 
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Dr. Courtney said:
Yes, you need to integrate. One approach is described in the linked paper:

http://arxiv.org/ftp/arxiv/papers/0903/0903.1555.pdf
I actually have one more question. Would I need to integrate twice to go from jerk to acceleration then from acceleration to velocity or could I just take the integral of the equation I posted of acceleration as a function of time. Still reading through paper it might answer this.
 

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