Do Invertible Matrices Influence the Equality of Characteristic Polynomials?

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Homework Help Overview

The discussion revolves around the relationship between the characteristic polynomials of two nXn matrices A and B, specifically under the condition that A is invertible. The original poster attempts to prove that P_{AB}(x) equals P_{BA}(x) based on properties of determinants.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants question the validity of the original poster's reasoning regarding determinants and their connection to characteristic polynomials. There is a suggestion to consider the definition of characteristic polynomials in terms of determinants.

Discussion Status

The discussion is ongoing, with participants providing hints and questioning assumptions. Some express frustration with direct answers being given instead of guidance, indicating a focus on exploring the problem rather than resolving it outright.

Contextual Notes

There is a mention of forum guidelines that discourage providing complete solutions, emphasizing the need for hints and guidance instead. The original poster's assumption about the determinant of an invertible matrix being zero is also under scrutiny.

talolard
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Homework Statement


Let A and B be to nXn matrices and A is invertible. Prove: [tex]P_{AB}(x)=P_{BA}(x)[/tex]


The Attempt at a Solution


Since A is invertible we have det(A)=0. [tex]det(AB)= det(A)det(B)=0det(B)=0 ->P_{AB}(x)=P_{BA}(x)=0[/tex]

Is that correct?




[
 
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netheril96, you are supposed to give hints and help. Not work out people's problems for them. Read the forum guidelines.
 
Dick said:
netheril96, you are supposed to give hints and help. Not work out people's problems for them. Read the forum guidelines.

But this problem is so easy that the only hint I can give is the direct answer
 
talolard said:

Homework Statement


Let A and B be to nXn matrices and A is invertible. Prove: [tex]P_{AB}(x)=P_{BA}(x)[/tex]

The Attempt at a Solution


Since A is invertible we have det(A)=0. [tex]det(AB)= det(A)det(B)=0det(B)=0 ->P_{AB}(x)=P_{BA}(x)=0[/tex]

Is that correct?

[

Talolard, the determinants you've written down are all just numbers. They don't have anything to do with the characteristic polynomial. What's the definition of a characteristic polynomial in terms of a determinant? Besides if A is invertible it's determinant is NOT 0.
 
netheril96 said:
But this problem is so easy that the only hint I can give is the direct answer

It's not 'so easy' for a lot of people. If the only hint you can think of is to give the solution, don't. Find another thread to work on. Could you remove the post with your proof in it please?
 
Dick said:
It's not 'so easy' for a lot of people. If the only hint you can think of is to give the solution, don't. Find another thread to work on. Could you remove the post with your proof in it please?

Deleted
 
netheril96 said:
Deleted

Thanks!
 
You may wish to consider similar matrices here
 

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