Do Lorentz Transformations Affect Simultaneity in Different Frames?

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SUMMARY

The discussion centers on the application of Lorentz transformations to analyze simultaneity in different inertial frames, specifically regarding two lightning strikes on a tree and a pole. The spacetime coordinates for the events are given as (x=0, t=10μs) for the tree and (x=30000m, t=10μs) for the pole, which are simultaneous in the ground frame. When transforming to the rocket's frame moving at 0.5c, the coordinates change to x'=-1732.05m, t'=11.547μs for the tree and x'=32908.95m, t'=-46.18μs for the pole. The participant questions why the spatial separation in the rocket's frame exceeds 30000m, indicating a misunderstanding of simultaneity and the need to compare positions at the same time.

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DarkMalice
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Anyone help. I know I must be doing this wrong somehow

Lightning hits both a tree and a pole. The spacetime coordinates for each is (x=0, t=10us) for the tree and (x=30000m, t=10us) for the pole relative to the ground. Therefore they occur simultaneously relative to the ground. A rocket comes whizzing by at 0.5c in the x-direction. Find the spacetime coordinates relative to the rocket. Do the events happen simultaneously in the rocket's frame? (us is microseconds by the way)


First and foremost, I was able to find the factor y as y= 1/(1-.05^2)^.5 = 1.1547

Using Lorentz transformations
For the tree
x'= 1.1547 X [0 -(0.5c)(10us)]
= -1732.05m

t'=1.1547 X [10us -(0.5c)(0)/c^2]
= 11.547us

For the pole
x'= 1.1547 X [30000-(0.5c)(10us)]
= 32908.95

t'= 1.1547 X [10us - (0.5c)(30000)/c^2]
=-46.18us


What I want to know is why is x'(pole)-x'(tree)> 30000? Shouldn't the distance between both poles go through length contraction in the rocket's frame and therefore be shorter than 30000?

Please someone help
 
Physics news on Phys.org
You're comparing the location of the tree and the location of the pole at different times in the rocket's frame. To find the distance between the two, you need to compare where they are at the same time.
 

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